How to build a loop through every column and row of a cell

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Julia Gorman 2022-7-25

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https://ww2.mathworks.cn/matlabcentral/answers/1767630-how-to-build-a-loop-through-every-column-and-row-of-a-cell

回答： Voss 2022-7-25

I have a 32 x 3 MATLAB cell and I want to loop through every one of the 96 cells to find the single largeset value contained in all of them? How might I go about doing that.

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Answer 1

Voss 2022-7-25

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https://ww2.mathworks.cn/matlabcentral/answers/1767630-how-to-build-a-loop-through-every-column-and-row-of-a-cell#answer_1014835

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% first, I create a 32x3 cell array of random 10x10 matrices
C = arrayfun(@(x)randn(10),zeros(32,3),'uni',false)
C = 32×3 cell array
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
    {10×10 double}    {10×10 double}    {10×10 double}
% now loop through all the cells and store 
% the largest value in each cell
C_max = zeros(size(C));
for ii = 1:numel(C)
    C_max(ii) = max(C{ii}(:));
end
C_max
C_max = 32×3
    2.0129    2.2185    2.5962
    1.6750    2.0335    2.5236
    2.5415    2.8507    2.3550
    3.0317    3.2665    2.4372
    3.1738    2.4802    2.2340
    2.2609    2.5011    3.6321
    2.3977    1.9500    2.2795
    2.4205    2.4711    2.3772
    2.7915    1.6535    2.1038
    2.8421    2.0512    2.6285
% finally, the single largest value
C_max = max(C_max(:))
C_max = 4.0026