How to use regex to obtain double values?

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Atanu
Atanu 2022-7-29
评论： Atanu 2022-7-29
I have an array of strings which contains some units. I have attahced the array.
unq = ["10 lux";"10lux";"15";"15.0";"15.5 Lux";"15luX";"15lux";"20lux";"36lux";"42lux";"9lux"]
They are put in different format on different days. So, I get 11 unique entries. I used the following code only to keep the numeric part.
trimData = strtrim(unq);
regexData = regexp(trimData,'\d*','Match');
cleanedData = cell(numel(unq),1);
for kk = 1:numel(unq)
if length(regexData{kk}) >= 1
cleanedData{kk} = regexData{kk}(1);
end
end
cleanedData = str2double(string(cleanedData));
I got
cleanedData = [10;10;15;15;15;15;15;20;36;42;9]
I am not getting 15.5 in the resulting array. How do get the numbers in which the digits after decimal place is not '0'? How do I write a regular expression for that?

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采纳的回答

Walter Roberson
Walter Roberson 2022-7-29
编辑：Walter Roberson 2022-7-29
Ran in:
Extending to the possibility of fraction values that start with decimal point (with no leading zero), and extending to support negative values
But not extending to exponential format:
unq = ["10 lux";"-10lux";"15";"15.0";"15.5 Lux";"15luX";"15lux";"20lux";"36lux";"42lux";".9lux"]
unq = 11×1 string array
"10 lux" "-10lux" "15" "15.0" "15.5 Lux" "15luX" "15lux" "20lux" "36lux" "42lux" ".9lux"
regexData = regexp(unq, '(-?\d+(\.\d*)?)|(-?\.\d+)', 'match', 'once')
regexData = 11×1 string array
"10" "-10" "15" "15.0" "15.5" "15" "15" "20" "36" "42" ".9"

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