loop a matrix through disorder columns indices
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I have a matrix A which has 100 rows and 5 columns, I would like to iterate the matrix with disorder indices of columns and save them in each iteration, column indices [2;5;3;4;1]. 1st iteration: get all the rows of A with column 2 then do some processes. 2nd iteration : get all the rows of A with columns 2 and 5. ..... last iteration: get all the rows and columns of A. Anyone helps me to implement it on Matlab environment please.
回答（1 个）
Hi!
What about this below!
% Dummy A
A = randi(4, 100, 5 ) ;
%
B = [] ;
for cIdx = [2 5 3 4 1]
B = [B, A(:, cIdx )]
end
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2022-7-31
2022-7-31
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