loop a matrix through disorder columns indices

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Yousuf Khan
Yousuf Khan 2022-7-31
回答： Abderrahim. B 2022-7-31
I have a matrix A which has 100 rows and 5 columns, I would like to iterate the matrix with disorder indices of columns and save them in each iteration, column indices [2;5;3;4;1]. 1st iteration: get all the rows of A with column 2 then do some processes. 2nd iteration : get all the rows of A with columns 2 and 5. ..... last iteration: get all the rows and columns of A. Anyone helps me to implement it on Matlab environment please.

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回答（1 个）

Abderrahim. B
Abderrahim. B 2022-7-31
Ran in:
Hi!
What about this below!
% Dummy A
A = randi(4, 100, 5 ) ;
%
B = [] ;
for cIdx = [2 5 3 4 1]
B = [B, A(:, cIdx )]
end
B = 100×1
3 3 3 4 1 4 1 2 1 4
B = 100×2
3 2 3 3 3 3 4 4 1 1 4 3 1 4 2 1 1 3 4 3
B = 100×3
3 2 2 3 3 1 3 3 3 4 4 1 1 1 1 4 3 3 1 4 4 2 1 1 1 3 2 4 3 2
B = 100×4
3 2 2 1 3 3 1 2 3 3 3 4 4 4 1 2 1 1 1 2 4 3 3 2 1 4 4 2 2 1 1 2 1 3 2 2 4 3 2 3
B = 100×5
3 2 2 1 4 3 3 1 2 1 3 3 3 4 2 4 4 1 2 1 1 1 1 2 4 4 3 3 2 4 1 4 4 2 3 2 1 1 2 4 1 3 2 2 2 4 3 2 3 2

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