How to find x value for a known y in array plot?
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I have to draw a plot based on a long matrix, which I did, after that I got the maximum of y value (max(y)) but I need the x value for the known y value y=0.8*max(y) THIS y value is not included in the matrix, so I can't use the Index of the maximum to get my x
I did found a similar question https://de.mathworks.com/matlabcentral/answers/258556-how-to-i-find-a-x-value-from-a-given-y
and tried to apply the same code x(y==0.8*max(y)) but I get a 0x1 empty column vector.
Can anyone help me out? thanks in advance
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采纳的回答
Star Strider
2022-8-7
Possibly:
idx = find(diff(sign(y - 0.8*max(y))));
xvals = x(idx)
That should find the closest indices to all of them.
2 个评论
Star Strider
2022-8-10
编辑:Star Strider
2022-8-11
Without the data, it is difficult to determine that. It will be necessary to define a specific x-value to determine which is closest.
Example —
x = linspace(0, 20, 500); % Create Data
y = sin(2*pi*x) + cos(3*pi*x) - (x-10).^2/100; % Create Data
idx = find(diff(sign(y - 0.8*max(y))));
xvals = x(idx)
x_desired = 10; % Define Target X-Value
[xabsdist,xidx] = min(abs(xvals - x_desired));
% idx(xidx)
% x(idx(xidx))
% y(idx(xidx))
fprintf(1,'Target Y-Value: %.3f\nClosest X-Value: %.3f\nCorresponding Y-Value: %.3f\nY-Distance |Desired-Actual|: %.3f\n', 0.8*max(y), x(idx(xidx)), y(idx(xidx)), abs(0.8*max(y)-y(idx(xidx))))
figure
plot(x, y, 'DisplayName','Data')
hold on
plot(xvals, y(idx), 'ks', 'DisplayName','Closest Indices')
plot(x(idx(xidx)), y(idx(xidx)), 'rs', 'MarkerFaceColor','r', 'DisplayName','Closest X-Value')
yline(0.8*max(y), '--g', 'DisplayName','0.8\times y_{max} Reference')
xline(x_desired, '--r', 'DisplayName','Desired X-Value')
hold off
grid
legend('Location','best')
This uses synthetic data, however it should work for your actual data.
Make appropriate changes to get the result you want. (It is also possible to interpolate to get the exact x- and y-values rather than just using the indices.)
EDIT — (11 Aug 2022 at 1:00)
Added interpolation example.
Example —
tgt = 0.8*max(y);
L = numel(x);
for k = 1:numel(idx)
idxrng = max(1,idx(k)-1) : min(L,idx(k)+1);
xv(k) = interp1(y(idxrng), x(idxrng), tgt);
end
[xvabsdist,xvidx] = min(abs(xv - x_desired));
fprintf(1,'Closest X-Value: %.3f\nDistance |xv - x-desired|: %.3f\n', xv(xvidx),xvabsdist)
figure
plot(x, y, 'DisplayName','Data')
hold on
plot(xv, ones(size(xv))*tgt, 'ks', 'DisplayName','Exact X-Values')
plot(xv(xvidx), tgt, 'rs', 'MarkerFaceColor','r', 'DisplayName','Closest X-Value')
yline(0.8*max(y), '--g', 'DisplayName','0.8\times y_{max} Reference')
xline(x_desired, '--r', 'DisplayName','Desired X-Value')
hold off
grid
legend('Location','best')
.
更多回答(4 个)
David Hill
2022-8-7
[~,idx]=min(abs(y-.8*max(y)));%.8*max(y) is not part of the y-array, find the closest y-idx to that value
x(idx)
Bruno Luong
2022-8-10
编辑:Bruno Luong
2022-8-10
*
x = linspace(-3,3);
Assuming your data are monotonic on the neighborhood of the max
y = exp(-x.^2);
[maxy, imax] = max(y);
yt = 0.8*maxy;
% left side
i1 = find(y<yt & 1:length(y)<imax, 1, 'last');
if isempty(i1)
error('no x found on the left side')
end
xl = interp1(y([i1 i1+1]), x([i1 i1+1]), yt)
% right side
i2 = find(y<yt & 1:length(y)>=imax, 1, 'first');
if isempty(i2)
error('no x found on the right side')
end
xr = interp1(y([i2-1 i2]), x([i2-1 i2]), yt)
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