Add and subtract matrix element consecutively
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My assignment asks me to add and subtract elements in a matrix consecutively and I am using a for loop to solve.
Example
a = 1:10;
temp_sum = 0;
for i = 1:10
sum_a = temp_sum + (-1)^i*a(i);
temp_sum = sum_a;
end
temp_sum
I wonder if there is other more elegant way to solve this problem. Thanks!
采纳的回答
Since you already solved your own homework, I see no problem in providing you with some code.
The main thing to remember is that a vectorized solution is faster than a loop (if a direct function exists).
A=zeros(200,1000);
tic
A1=A;
for n=1:numel(A),A1(n)=A1(n)+1;end
toc
tic
A2=A;
A2=A2+ones(size(A2));
toc
% Or even better in this case: A3=A3+1;
You need to find a way to generate the full array efficiently.
You already saw you can use (-1)^n to alternate positive and negative factors. How would you write such an expression to generate the vector you need?
% This is a tricky step that may be hard to debug: you need .* for
% element-wise multiplication
[1 2 3 4].*[1 -1 1 -1]
Now, how would you sum these elements?
更多回答（1 个）
a = 1:10;
%using sum
sum(a.*(-1).^a)
Another approach is to take advantage of the fact that multiplication of a row vector and a column vector (of same number of elements, of course) will result in multiplicative sum of the two.
a - 1xn, b - nx1; a*b = a1*b1+a2*b2*+......+an*bn
%one liner
a
(-1).^a'
a*(-1).^a'
2 个评论
Rik
2022-8-8
Please attempt to teach the solution for homework questions, instead of just giving it.
You may also want to explain what is happening in your second solution. It will not be immediately apparent to a novice why that works or what is going on.
Dyuman Joshi
2022-8-8
You are right, RIk, I should have done that initially.
I have edited my answer now.
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