Add and subtract matrix element consecutively

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Hoang Trung Le
Hoang Trung Le 2022-8-8
评论： Dyuman Joshi 2022-8-8
Ran in:
My assignment asks me to add and subtract elements in a matrix consecutively and I am using a for loop to solve.
Example
a = 1:10;
a = 1×10
1 2 3 4 5 6 7 8 9 10
temp_sum = 0;
for i = 1:10
sum_a = temp_sum + (-1)^i*a(i);
temp_sum = sum_a;
end
temp_sum
temp_sum = 5
I wonder if there is other more elegant way to solve this problem. Thanks!

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采纳的回答

Rik
Rik 2022-8-8
Ran in:
Since you already solved your own homework, I see no problem in providing you with some code.
The main thing to remember is that a vectorized solution is faster than a loop (if a direct function exists).
A=zeros(200,1000);
tic
A1=A;
for n=1:numel(A),A1(n)=A1(n)+1;end
toc
Elapsed time is 0.007344 seconds.
tic
A2=A;
A2=A2+ones(size(A2));
toc
Elapsed time is 0.003079 seconds.
% Or even better in this case: A3=A3+1;
You need to find a way to generate the full array efficiently.
You already saw you can use (-1)^n to alternate positive and negative factors. How would you write such an expression to generate the vector you need?
% This is a tricky step that may be hard to debug: you need .* for
% element-wise multiplication
[1 2 3 4].*[1 -1 1 -1]
ans = 1×4
1 -2 3 -4
Now, how would you sum these elements?

更多回答（1 个）

Dyuman Joshi
Dyuman Joshi 2022-8-8
编辑：Dyuman Joshi 2022-8-8
Ran in:
What you are doing in a loop, can be done via element-wise multiplication as well.
You can make an array for the corresponding powers of -1, multiply it with a and sum it.
a = 1:10;
%using sum
sum(a.*(-1).^a)
ans = 5
Another approach is to take advantage of the fact that multiplication of a row vector and a column vector (of same number of elements, of course) will result in multiplicative sum of the two.
a - 1xn, b - nx1; a*b = a1*b1+a2*b2*+......+an*bn
%one liner
a
a = 1×10
1 2 3 4 5 6 7 8 9 10
(-1).^a'
ans = 10×1
-1 1 -1 1 -1 1 -1 1 -1 1
a*(-1).^a'
ans = 5
  2 个评论
Rik
Rik 2022-8-8
Please attempt to teach the solution for homework questions, instead of just giving it.
You may also want to explain what is happening in your second solution. It will not be immediately apparent to a novice why that works or what is going on.
Dyuman Joshi
Dyuman Joshi 2022-8-8
You are right, RIk, I should have done that initially.
I have edited my answer now.

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