Passing values to PSO options

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Buddhi Wimarshana
评论： Buddhi Wimarshana 2022-8-8
Hi there,
How may I pass swarmSize variable value to opts in the PSO? I have included the particular code piece below. When I do as below, it seems 'swarmSize' doesn't get passed to opts. Many thanks in advance.
swarmSize = 10; %doesn't pass to opts??
opts = optimoptions(@particleswarm,...
'Display','iter',...
'PlotFcn','pswplotbestf',...
'SwarmSize', swarmSize,...
'MaxIterations',20,...
'UseVectorized',true,...
'UseParallel',false);
% Cost {function-handle}
cost = @(particlePosition) costfn(iStep,nn,swarmSize,nvars,particlePosition);
% PSO Call
[particlePosition,particleCost,exitflag,output] = particleswarm(cost,nvars-2,particlelb,particleub,opts);

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回答（1 个）

Alan Weiss
Alan Weiss 2022-8-8
Ran in:
It works for me. Here is a little test script:
fun = @(x)x(1)*exp(-norm(x)^2);
lb = [-5,-5];
ub = -lb;
opts = optimoptions('particleswarm',"SwarmSize",20,"Display","iter");
[sol,fv,ef,output] = particleswarm(fun,2,lb,ub,opts)
Best Mean Stall Iteration f-count f(x) f(x) Iterations 0 20 -0.02168 0.008792 0 1 40 -0.4151 -0.02415 0 2 60 -0.4151 -2.352e-05 1 3 80 -0.4151 -0.002245 2 4 100 -0.4151 -0.000726 3 5 120 -0.4151 0.015 4 6 140 -0.4151 0.004306 5 7 160 -0.4151 0.0146 6 8 180 -0.4151 -0.04039 7 9 200 -0.4151 -0.02363 8 10 220 -0.4151 -0.1728 9 11 240 -0.4177 -0.3032 0 12 260 -0.4177 -0.3321 1 13 280 -0.4206 -0.3799 0 14 300 -0.4288 -0.4074 0 15 320 -0.4288 -0.4167 1 16 340 -0.4288 -0.4254 2 17 360 -0.4289 -0.4278 0 18 380 -0.4289 -0.4283 1 19 400 -0.4289 -0.4286 0 20 420 -0.4289 -0.4288 1 21 440 -0.4289 -0.4289 2 22 460 -0.4289 -0.4289 3 23 480 -0.4289 -0.4289 0 24 500 -0.4289 -0.4289 0 25 520 -0.4289 -0.4289 1 26 540 -0.4289 -0.4289 0 27 560 -0.4289 -0.4289 0 28 580 -0.4289 -0.4289 0 29 600 -0.4289 -0.4289 1 30 620 -0.4289 -0.4289 2 Best Mean Stall Iteration f-count f(x) f(x) Iterations 31 640 -0.4289 -0.4289 0 32 660 -0.4289 -0.4289 0 33 680 -0.4289 -0.4289 0 34 700 -0.4289 -0.4289 0 35 720 -0.4289 -0.4289 1 36 740 -0.4289 -0.4289 0 37 760 -0.4289 -0.4289 0 38 780 -0.4289 -0.4289 0 Optimization ended: relative change in the objective value over the last OPTIONS.MaxStallIterations iterations is less than OPTIONS.FunctionTolerance.
sol = 1×2
-0.7071 0.0000
fv = -0.4289
ef = 1
output = struct with fields:
rngstate: [1×1 struct] iterations: 38 funccount: 780 message: 'Optimization ended: relative change in the objective value ↵over the last OPTIONS.MaxStallIterations iterations is less than OPTIONS.FunctionTolerance.' hybridflag: []
You see that there were 38 iterations and 780 function evaluations. This corresponds to a swarm size of 20: 20*38 = 760, plus 20 initial evaluations = 780 function evaluations.
Alan Weiss
MATLAB mathematical toolbox documentation
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Alan Weiss
Alan Weiss 2022-8-8
Ran in:
Try the code your way:
rng default
fun = @(x)x(1)*exp(-norm(x)^2);
lb = [-5,-5];
ub = -lb;
swarmSize = 20
swarmSize = 20
opts = optimoptions('particleswarm',"SwarmSize",swarmSize,"Display","iter");
[sol,fv,ef,output] = particleswarm(fun,2,lb,ub,opts)
Best Mean Stall Iteration f-count f(x) f(x) Iterations 0 20 -0.00953 0.005882 0 1 40 -0.02456 -0.001228 0 2 60 -0.05993 0.001832 0 3 80 -0.05993 -0.0008519 1 4 100 -0.08234 -0.005554 0 5 120 -0.2747 0.02441 0 6 140 -0.2747 0.02433 1 7 160 -0.3332 -0.01632 0 8 180 -0.3332 0.01548 1 9 200 -0.3332 -0.00039 2 10 220 -0.3332 0.00387 3 11 240 -0.3332 0.01008 4 12 260 -0.3332 -0.01568 5 13 280 -0.3332 0.005135 6 14 300 -0.3332 -0.0003027 7 15 320 -0.3332 -0.006723 8 16 340 -0.3797 -0.0914 0 17 360 -0.4253 -0.1851 0 18 380 -0.4263 -0.2863 0 19 400 -0.4272 -0.3619 0 20 420 -0.4285 -0.417 0 21 440 -0.4287 -0.4215 0 22 460 -0.4288 -0.4272 0 23 480 -0.4289 -0.4277 0 24 500 -0.4289 -0.4282 1 25 520 -0.4289 -0.4281 0 26 540 -0.4289 -0.4276 0 27 560 -0.4289 -0.4279 1 28 580 -0.4289 -0.4275 2 29 600 -0.4289 -0.4265 3 30 620 -0.4289 -0.427 4 Best Mean Stall Iteration f-count f(x) f(x) Iterations 31 640 -0.4289 -0.4237 5 32 660 -0.4289 -0.4249 6 33 680 -0.4289 -0.4257 7 34 700 -0.4289 -0.4283 8 35 720 -0.4289 -0.4286 0 36 740 -0.4289 -0.4284 0 37 760 -0.4289 -0.4288 0 38 780 -0.4289 -0.4289 1 39 800 -0.4289 -0.4289 0 40 820 -0.4289 -0.4289 1 41 840 -0.4289 -0.4289 0 42 860 -0.4289 -0.4289 0 43 880 -0.4289 -0.4289 0 44 900 -0.4289 -0.4289 0 45 920 -0.4289 -0.4289 0 Optimization ended: relative change in the objective value over the last OPTIONS.MaxStallIterations iterations is less than OPTIONS.FunctionTolerance.
sol = 1×2
-0.7071 0.0000
fv = -0.4289
ef = 1
output = struct with fields:
rngstate: [1×1 struct] iterations: 45 funccount: 920 message: 'Optimization ended: relative change in the objective value ↵over the last OPTIONS.MaxStallIterations iterations is less than OPTIONS.FunctionTolerance.' hybridflag: []
This time (with rng default for reproducibility) I get 45 iterations times 20 particles = 900 fevals, +20 initial fevals = 920 fevals, as shown. The options get passed as you wanted.
Alan Weiss
MATLAB mathematical toolbox documentation
Buddhi Wimarshana
Buddhi Wimarshana 2022-8-8
Oh silly me!!! have done a silly mistake, it works great...thanks Alan so much...really shouldn't have asked here, but didn't notice the mistake for hours, but I do now

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