In simulink, debouncing

2022 8 10
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更新时间：2022 8 21
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If u1>3, move on to the next condition. When sampling time is 1 second, if u1>3 for 3 seconds by de-bouncing method, we want to move on to the next condition. If u1 >3 in 1 second, but u1 < 3 in 2 seconds, the next condition is not passed.

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回答（1 个）

Muthukumar Ganesan
Muthukumar Ganesan 2022-8-21

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Hi,
Using stateflow, you can implement this with after function whereas using simulink counter logic has to be implemented.
Please find the attachements.
Thanks

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