In simulink, debouncing

2022 8 10
1 个回答
更新时间：2022 8 21
9 次查看（30 天）

0 个投票

If u1>3, move on to the next condition. When sampling time is 1 second, if u1>3 for 3 seconds by de-bouncing method, we want to move on to the next condition. If u1 >3 in 1 second, but u1 < 3 in 2 seconds, the next condition is not passed.

请先登录，再回答此问题。

回答（1 个）

Muthukumar Ganesan
Muthukumar Ganesan 2022-8-21

0 个投票

Hi,
Using stateflow, you can implement this with after function whereas using simulink counter logic has to be implemented.
Please find the attachements.
Thanks

类别

在 帮助中心 和 File Exchange 中查找有关 Stateflow 的更多信息

产品

版本

R2021b

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by