I want to create a binary matrix with a variable dimensions

2022 8 11
1 个回答
更新时间：2022 8 11
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0 个投票

I want to create a binary matrix of dimension k x M where k and M are user defined.(k is the number of rows and M is the number of column). And number of zeros and ones in each row are user defined. Also this binary matrix should be a function.

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James Tursa
James Tursa 2022-8-11
What have you done so far? What specific problems are you having with your code?
Nir Vaishnav
Nir Vaishnav 2022-8-11
for kk=1:lnk
m = input('How many zeroes do you need \n');
n = input('how many ones do you need\n');
lnk=nchoosek(m+n,n);
i=n+m;
if i<=1
disp('size of binary sequence is out of range');
else
%Binary sequence contains m zeros and n ones in any order
x1=zeros(1,m);
x1(randn(i,n))=1
%count down the number of switches in such a Binary sequence x1;
end
end
This is what i have done but it creates only arrays i dont understand how to make it into a matrix. and then convert into a function

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回答（1 个）

David Hill
David Hill 2022-8-11
编辑：David Hill 2022-8-11

0 个投票

k=10;
M=50;
O=randi(M+1,k)-1;%number of ones per row (number of zeros per row= 50 - O)
for n=1:k
m=[ones(1,O(n)),zeros(1,M-O(n))];
Matrix(n,:)=m(randperm(M));
end

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Nir Vaishnav
Nir Vaishnav 2022-8-11
if i change the value of k,M then it shows the error that left side matrix dimension is not equal to right side.
David Hill
David Hill 2022-8-11
You just need to clear Matrix or set Matrix = [ ] at the beginning.
k=10;
M=50;
Matrix=[];
O=randi(M+1,k)-1;%number of ones per row (number of zeros per row= 50 - O)
for n=1:k
m=[ones(1,O(n)),zeros(1,M-O(n))];
Matrix(n,:)=m(randperm(M));
end

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