How to plot a data in spherical coordinates?
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Let me explain, what I'm actually solving.
I'm solving Diffusion-Reaction equation(2D) in spherical coordinates(axis-symmetric case).
I'm solving this equation numerically. So at the end I'm getting 
, r, θ.
, r, θ.So I want to plot this function in r and θ plane instead of 
palne
in r and θ plane instead of palneI'm attaching data.mat file to this question
Can anyone help in this regard?
Thanks in advance.
采纳的回答
David Hill
2022-8-16
[x,y,z]=sph2cart(th,conc,r);
surf(x,y,z);
3 个评论
Jagadeesh Korukonda
2022-8-16
编辑：Jagadeesh Korukonda
2022-8-16
No it is giving different result, conc is not elavation angle. conc is a function of r and theta.
ψ(r, θ) is not ϕ.
Actually ψ is a function of ψ(r, θ, ϕ). I solved my solution for axis-symmetry case.
Let me explain, what I'm actually solving.
I'm solving Diffusion-Reaction equation(2D) in spherical coordinates(axis-symmetric case).
I'm solving this equation numerically. So at the end I'm getting 
, r, θ.
, r, θ.So I want to plot this function in r and θ plane instead of 
palne
in r and θ plane instead of palne
If you solve the equation in r and theta, you also get the solution C in r and theta. So plotting in the r-theta plane would simply mean
[R,THETA] = ndgrid(r,theta);
surf(R,THETA,C)
where C(i,j) = C(r(i),theta(j)).
So you plot over a rectangle with x-axis r and y-axis theta (0<=r<=R, 0<=theta<=2*pi).
If you want to plot in the x-y-plane (thus over the circle with radius R), you must convert to x and y coordinates via x = r*cos(theta), y= r*sin(theta).
Jagadeesh Korukonda
2022-8-17
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