Iterative code sequence error

Question

Matthew Worker 2022-8-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1781520-iterative-code-sequence-error

编辑： etrh3789 2023-1-4

f(i) = f(i-3)*f(i-1) - f(i-2) using f(1) = 1, f(2) = 1 and f(3) = 1.

function f = iterativeSequence(n)
  f(1) = 1;
  f(2) = 1;
  f(3) = 1;
  for i = 4:n
      f(n) = (f(i-3)*f(i-1))-f(i-2);
end

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Answer 1

Torsten 2022-8-18

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1781520-iterative-code-sequence-error#answer_1028645

在 MATLAB Online 中打开

f1 = 1;
f2 = 1;
f3 = 1;
n = 10;
f = sequence(n,f1,f2,f3)
f = 1×10
     1     1     1     0    -1    -1     1     0    -1    -1
function f = sequence(n,f1,f2,f3)
  if n < 4 
    disp('Choose bigger value for n');
    f = [f1 f2 f3];
    return
  end
  f = zeros(1,n);
  f(1) = f1;
  f(2) = f2;
  f(3) = f3;
  for i = 4:n
    f(i) = f(i-3)*f(i-1) - f(i-2);
  end
end