Pixel decomposition
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Sir, I`m new to matlab and doing a basic work on decomposition of pixels with the criteria as follows:
Denote the numbers of rows and columns in an original image as n1 and n2, the total number of pixels as n=n1*n2, and the gray pixel-values as Pn belongs (0.255), n=1,2,3etc . assume both n1 and n2 are multiples of 8. Each pn can be represented by 8 bits, , where B(n,t)={Pn/2^t} (1)In other words Pn=(B(n,t). 2t)
We call B(n,7),B(n,6)...B(n,3)the MSB, and B(n,2),B(n,1)the LSB. Then, collect the MSB of each pixel to form an MSB set that includes 5N bits.
Kindly formulate me the code for this computation
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Walter Roberson
2011-10-9
What output representation do you want?
You have
B(n,t)={Pn/2^t}
but that is not going to be a single bit except in the special case where Pn == 2^t exactly. Suppose for example that Pn is 3 and t is 1, then B(n,t) would be 3/2^1 which would be 1 1/2 .
Notice too that when defining MSB and LSB you go down to B(n,1) but not to B(n,0) . Thus you are always dividing by at least 2^1 and therefor have no mechanism to get at the bit with the least value (the one that contributes 0 or 2^0 to Pn)
Your notation
Pn=(B(n,t). 2t)
does not make any sense to me. Pn = Sum(B(n,t) * 2^t, t=1..8) would make more sense to me.
If my guess is correct about your desired output representation, then my suspicion is that the desired output can be produced in one expression. On the other hand, I suspect that your talk about B(n,t) is an indication of how you are being directed to code this.
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Image Analyst
2011-10-9
I also had trouble figuring out what was wanted. I didn't know if the instructor simply wanted the lower 5 bits and/or upper 5 bits of the image, like this:
lower5bits = bitand(grayImage, uint8(32));
upper5bits = bitand(grayImage, uint8(256-32));
or something like that.
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Walter Roberson
2011-10-9
I think it is the upper 5 bits being asked for, but extracted I think, or at least shifted down.
One thing to watch out for is that the description of the values does not preclude floating point storage of the Pn values.
Dinesh Ranganathan
2011-10-12
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2011-10-9
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