for loop to scan matrix and output a new matrix

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Laura Steel
Laura Steel 2022-8-19
评论： Laura Steel 2022-8-19
I would like to take an e.g. 8x1 matrix such as the one below:
0
1
0
1
1
1
0
1
and I would like to scan through it and generate a new matrix of the same dimensions, following the rules below.
  • Make the first value of the new matrix the same as the first value of the original matrix.
  • Then from here on:
  • If the value is 0, add a 0 to the new matrix.
  • If the value is 1 AND the value above it is 1, assign a 0 to the new matrix.
  • However, if the value is 1 but the value above it is 0, then assign a 1 to the new matrix.
So, the resulting matrix should be:
0
1
0
1
0
0
0
1
Any help, with clear notation of what each part of the for loop is doing, would be much appreciated! Many thanks.
  2 个评论
Laura Steel
Laura Steel 2022-8-19
编辑：Walter Roberson 2022-8-19
I think I may have worked something out! But I am not sure it is the best/simplest way of doing it?
matrix = [0; 1; 0; 0; 1; 1; 1; 1; 0; 0; 1; 1; 0];
matrix_new = zeros(13,1);
for i = 1:length(matrix)
if i == 1
matrix_new(i,1) = matrix(1,1);
end
if matrix(i,1) == 0
matrix_new(i,1) = 0;
end
if matrix(i,1) == 1 & matrix(i-1,1) ==0
matrix_new(i,1) = 1
end
if matrix(i,1) == 1 & matrix(i-1,1) ==1
matrix_new(i,1) = 0
end
end

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回答（1 个）

Walter Roberson
Walter Roberson 2022-8-19
Ran in:
matrix = [0; 1; 0; 0; 1; 1; 1; 1; 0; 0; 1; 1; 0];
matrix_new = [matrix(1); matrix(2:end) & ~matrix(1:end-1)]
matrix_new = 13×1
0 1 0 0 1 0 0 0 0 0
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Walter Roberson
Walter Roberson 2022-8-19
Ran in:
inf and -inf are not a problem, but nan is a problem.
~[-inf inf]
ans = 1×2 logical array
0 0
~nan
Error using ~
NaN values cannot be converted to logicals.

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