Vector as ItemsData property in List Box

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Oskar Kilgus 2022-8-20

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回答： Oskar Kilgus 2022-8-21

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Hi all,

im coding a fairly easy app with app designer and im struggling with the input/output for List Box property "ItemsData".

What i want to do is to show the user 2 options ("Items") in a list-box. These options then lead to vectors of 2 numbers ("ItemsData"). Lets say:

With ItemsData(Option 1) = [2950 3350] and ItemsData(Option 2) = [3600 4500]

Now i want to use these 2 integers in my main function and i cant figure out how to do the indexing right. I tried using a cell array as ItemsData with combined indexing:

A = B{1,1}(1,1)

which leeds to an error because of the curly brackets.

If it is any easier with a Switch or DropDown its fine too! There are just 2 options.

Thanks for any help on this!

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Oskar Kilgus 2022-8-21

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I found a way to do it (If anyone is having trouble with this issue in the future)

1) List-Box ItemsData as 1x2 numeric vector:

[1 2]

2) value-changed function callback:

% Value changed function: choosefromListBox
        function choosefromListBoxValueChanged(app, event)
            app.whatever = str2num(app.choosefromListBox.Value)
        end

3) reference in other function:

app.whatever(1,1) %returns 1

______________________________

Thanks @Simon Chan for your effort!

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Simon Chan 2022-8-21

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Suppose the listbox is defined as follows and ItemsData are given in your example.

app.ListBox = uilistbox(app.UIFigure);

You may get the data directly via the following:

A = app.ListBox.Value

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Simon Chan 2022-8-21

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Could you please check whether the following lines gives the correct values to you or not?

app.choosefromListBox.Value(1)      % gives 2950 to another function
app.choosefromListBox.Value(2)      % gives 3350 to another function

Oskar Kilgus 2022-8-21

编辑：Oskar Kilgus 2022-8-21

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I tried exactly that (see the code i supplied) and it resulted in the error

"'Value' must be a double scalar within the range of 'Limits'."

The interesting value at the end of the function is m(o,:) = mean(p). I tried it again and now i end up with m=[0; NaN]. For the next iteration i still end up with the error message above!

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