How to generate a binary matrix with a fixed sum in rows and a changeable sum in columns?

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Hello everyone !
i have a binary matrix (M,N) .I want to get sum equal to 1 in each row and in columns sum varies between [1 and 6], the sum of all matrix equal to M.
i will be grateful if you could help me
  3 个评论
Ideth Kara
Ideth Kara 2022-8-21
how can i put "1" with different index in columns in order to get sum = 3 in each columns and "1" in each row
Torsten
Torsten 2022-8-22
What about
[1 0
1 0
0 1
0 1
0 1
0 1]
?
Do you see how to construct one such matrix ?
Of course, you can permute the rows arbitrarily - the resulting matrix will still fulfill the requirements.

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回答(1 个)

Bruno Luong
Bruno Luong 2022-8-21
编辑:Bruno Luong 2022-8-21
A=kron(eye(5),ones(3,1));
A=A(randperm(end),randperm(end))
A = 15×5
0 0 0 0 1 1 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 1 0 0 1 0 0 0 0 1 0 0
sum(A,1)
ans = 1×5
3 3 3 3 3
sum(A,2)
ans = 15×1
1 1 1 1 1 1 1 1 1 1
  4 个评论
Bruno Luong
Bruno Luong 2022-8-22
编辑:Bruno Luong 2022-8-22
The first line create the specific matrix that meet the row/column sum requirements.
The second line permutes rows and columns randomly, create a new random matrix, the sums are invariants under these operations, so the new matrix still meets the sum requirements.

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