Painters doesn't render line styles properly
显示 更早的评论
Hey there! I'm trying to export a figure as a pdf, and as such I set painters as the renderer for my figure. However, I don't seem to be getting the correct linestyles that I specify. Here's a mwe of what is happening:
x=linspace(0,1,100);
[X,Y]=meshgrid(x);
Z=peaks(100);
set(gcf,'Renderer','painters');
hold all
surf(X,Y,Z)
shading interp
contour3(X,Y,Z+1,[1,1],'LineStyle','--','LineWidth',1,'LineColor','w')
contour3(X,Y,Z+1,[2,2],'LineStyle','-.','LineWidth',1,'LineColor','w')
view(2)
As you can see the plot shows solid lines. By increasing the linewidth I see that the lines are actually dashed and dotted, but as they are they are pretty unusable. Anyone knows how to fix this issue?
3 个评论
Jaime Abad Arredondo
2022-8-23
Rik
2022-8-23
Perhaps using plot to create the lines might work better?
It seems like the behavior of plot3 and contour3 is the same... See the result below. I have also added the same figure generated with smaller matrices and you can see that the lines appear properly. I might have to resample the contour lines with less data points... A bit of a bummer considering that with openGL it works straight away.
figure(1)
clf
set(gcf,'Renderer','painters');
tiledlayout(1,2)
N0v=[20,100];
for j=1:length(N0v)
nexttile()
x=linspace(0,1,N0v(j));
[X,Y]=meshgrid(x);
Z=peaks(N0v(j));
hold all
surf(X,Y,Z)
shading interp
levels=[0,1];
cs={'w','r'};
lst={'-.','--'};
for i=1:length(levels)
M=contour3(X,Y,Z,levels(i)*[1,1],'LineColor','none','Visible','off');
c=1;
aux=true;
while aux
height_contour=M(1,c);
NP_cont=M(2,c);
x=M(1,c+(1:NP_cont));
y=M(2,c+(1:NP_cont));
z=ones(size(x))*(height_contour+1);
plot3(x,y,z,...
'LineStyle',lst{i},'LineWidth',1,...
'Color',cs{i})
c=c+NP_cont+1;
if c>size(M,2)
aux=false;
end
end
end
view(2)
end
回答（1 个）
Hi,
From the information you have provided, I understand that you are facing an issue getting the correct linestyles while setting the renderer for the figure as “painters.” Also, setting the renderer as “painters” works for you in the case of small matrices.
Since you have tried “OpenGL,” you can also use “zbuffer” to get the correct linestyles. Here is the sample code:
set(gcf, 'Renderer', 'zbuffer');
You can refer to the following documentation to know more about set and Renderer:
- https://www.mathworks.com/help/releases/R2023a/matlab/ref/set.html
- https://www.mathworks.com/help/releases/R2023a/matlab/ref/matlab.ui.figure-properties.html#prop_Renderer
I hope it helps.
2 个评论
Rik
2023-10-11
Wouldn't a doc page about the renderers make more sense as a reference?
Jaime Abad Arredondo
2023-10-11
编辑：Jaime Abad Arredondo
2023-10-11
Thanks for the suggestion!
As I see from the internet, z-buffer is not supported by matlab from release 2014b. In fact, when looking at the renderers page from mathworks, the term 'z-buffer' doesn't appear on the page. Setting it as a render engine still works though (see below). However this doesn't solve the issue at hand, since z-buffer generates the images by rasterizing, and therefore can't be properly exported as a vector file.
x=linspace(0,1,1000);
[X,Y]=meshgrid(x);
Z=peaks(1000);
set(gcf,'Renderer','zbuffer');
hold all
surf(X,Y,Z)
shading interp
contour3(X,Y,Z+1,[1,1],'LineStyle','--','LineWidth',1,'LineColor','w')
contour3(X,Y,Z+1,[2,2],'LineStyle','-.','LineWidth',1,'LineColor','r')
view(2)
类别
在 帮助中心 和 File Exchange 中查找有关 Graphics Performance 的更多信息
2022-8-23
2023-10-11
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
