I am getting Error using deval

11 次查看(过去 30 天)
nune pratyusha
nune pratyusha 2022-8-26
编辑: Torsten 2022-8-26
function yd = hyperchaos(t,y) %%%% selecting some cases for publication
global aa bb dd aa =3.55;
dd = 0;
mm=1;
n1 =1-aa*(y(2))*y(3);
n2 =1*y(3)*abs(y(3))-(y(3));
n3 =1*(mm*(abs(y(1))-dd))-bb*y(3);
n4 = 0 ;
A=[ 0 0 0 0
0 0 0 0
0 0 0 0
0 0 0 0];
B=[n1
n2
n3
n4];
yd=A*y+B;
clear
format long
global aa bb dd cc kk ee rr mm mm2 nn
dt=5*10^(-3);
tspan=(0:dt:500);
for i = 1:1:1
i
bb = -5+ (i-1)*0.025
dd = 0;
Y0=[0 5 0 0];
sol = ode45(@hyperchaos,[tspan(1) tspan(end)],Y0);
ss = deval(sol,tspan)';
s = ss(1500:end,:);
backColor = [0.5 0.5 0.5];
plot(s(1:end,1),s(1:end,2),'g'); xlabel('X');ylabel('Y')
drawnow
end
error:
>> main
i =
1
bb =
-5
Warning: Failure at t=2.738123e+00. Unable to meet integration tolerances without reducing the step size below
the smallest value allowed (7.105427e-15) at time t.
> In ode45 (line 351)
In main (line 23)
Error using deval (line 137)
Attempting to evaluate the solution outside the interval [0.000000e+00, 2.738123e+00] where it is defined.
Error in main (line 24)
ss = deval(sol,tspan)';
>>

回答(1 个)

Torsten
Torsten 2022-8-26
编辑:Torsten 2022-8-26
Your integration could not be continued beyond t = 2.738123.
So you try to evaluate the solution in a region where you have no data available.

类别

Help CenterFile Exchange 中查找有关 Image Segmentation and Analysis 的更多信息

标签

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by