i tried to find if there are perfect numbers in the code stating that 1 should be square of other in the same matrix or array

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Hannah
Hannah 2022-8-28
编辑： Hannah 2022-8-28
function b = Squared(a) n=length(a) for i=1:n for j=i:n if a(i)*a(i)==a(j) b=true break else b=false end end

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Swaroopa
Swaroopa 2022-8-28
编辑：Swaroopa 2022-8-28
Hi Hannah,
You can sort the array or matrix and then use the same code.
You can also use indentation rules for better clarity.
function output = squared(arr)
n=length(arr)
output=false
for i=1:n
for j=i:n
if arr(i)*arr(i)==arr(j)
output=true
break
else
output=false
end
end
end
end
Hope it helps

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