Fill up submatrix along third dimension with two dimensional matrix

2 次查看（过去 30 天）
Michael Stollenwerk
编辑： Bruno Luong 2022-8-29
Given a p by p by N array, e.g. p=3 and N=4,
x = NaN(3,3,4);
I can easily fill up the 1 by 1 by N submatrix given a "1 by 1 matrix"doing
x(1,1,:) = 1;
But what if I want to fill up the 2 by 2 by N submatrix like this
x(1:2,1:2,:) = [1 2; 3 4];
This does not work.
How could I do it elegantly?

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采纳的回答

Bruno Luong
Bruno Luong 2022-8-29
编辑：Bruno Luong 2022-8-29
x(1:2,1:2,:) = repmat( [1 2; 3 4], 1, 1, size(x,3));
I would love to have MATLAB indexing to behave with auto expansion, but probably many users would be unhappy and complain because of coding error becoming silence.

更多回答（1 个）

Torsten
Torsten 2022-8-29
Ran in:
x = NaN(3,3,4);
x(1:2,1:2,:) = repmat([1 2; 3 4],1,1,4);
x
x =
x(:,:,1) = 1 2 NaN 3 4 NaN NaN NaN NaN x(:,:,2) = 1 2 NaN 3 4 NaN NaN NaN NaN x(:,:,3) = 1 2 NaN 3 4 NaN NaN NaN NaN x(:,:,4) = 1 2 NaN 3 4 NaN NaN NaN NaN

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