Reshaping a matrix with different column sizes to a vector
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Hello,
Suppose you have a matrix that the number of columns for each row is different (the matrix is 100*132 but not every row has 132 data. Row 1 only has 21 columns and the rest is zero. Row 2 has 23 columns and the rest is zero and so on.
I want to reshape this matrix into a vector in which all of the rows of the original matrix are attached but I don't want the zeros. This is because I want to calculate the median of all elements and if I have the zeros, this will change the result.
For example, assume that the original matrix is:
M = [ 2 3 4 0 0 0; 1 3 6 2 1 0; 1 2 2 1 0 0 ]
and I want to reshape the above matrix to a vector like this:
A = [ 2 3 4 1 3 6 2 1 1 2 2 1 ]
that includes all numbers and excludes zeros.
I know the number of nonzero values in each row. They are available in an array like: Num = [3; 5; 4]
I tried this command but it did not work: reshape( M(:,1:Num(:,1)) , 1 , [])
It only considers the first value in Num and returns this vector instead:
[ 2 3 4 1 3 6 1 2 2 ]
Thank you for your help.
采纳的回答
This code will concatenate exactly the number of values from each row, as given in Num, regardless of the values in the row:
M = [2 3 4 0 0 0; 1 3 6 2 1 0; 1 2 2 1 0 0];
Num = [3; 5; 4];
N = num2cell(M,2);
N = cellfun(@(v,n)v(1:n), N, num2cell(Num(:)), 'UniformOutput',false);
N = [N{:}];
For example if we change values at position Num in each row to zero:
M = [2 3 0 0 0 0; 1 3 6 2 0 0; 1 2 2 0 0 0 ];
then we correctly get
N = [2 3 0 1 3 6 2 0 1 2 2 0]
更多回答（1 个）
Mischa Kim
2015-2-18
Maryam, how about
A = M';
A(A==0) = []
3 个评论
Maryam Mohammadipour
2015-2-18
Mischa Kim
2015-2-18
Nope. This works as is. Just give it a try.
Maryam Mohammadipour
2015-2-18
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