linear independent set formation

4 次查看（过去 30 天）
sanket neharkar
sanket neharkar 2022-9-3
评论： Bruno Luong 2022-9-5
show that {1,cost,cos2t.......cos6t} is linearly independent
using matlab code
can anyone help

请先登录，再回答此问题。

采纳的回答

Bruno Luong
Bruno Luong 2022-9-3
Ran in:
t = rand(1,7)*2*pi;
independent = rank(cos((0:6)'.*t)) == 7
independent = logical
1
  4 个评论
显示 2更早的评论
Matt J
Matt J 2022-9-5
@sanket neharkar but surely you can modify the answer appropriately.
Bruno Luong
Bruno Luong 2022-9-5
Ran in:
t = rand(1,7)*2*pi;
independent = rank(cos(t).^((0:6)')) == 7
independent = logical
1

请先登录，再进行评论。

更多回答（1 个）

Paul
Paul 2022-9-5
Ran in:
A set of functions fi(t) is linearly indepenedent if the only solution to
a1*f1(t) + a2*f2(t) .... an*fn(t) = 0 (1)
is ai = 0 for all values of t.
If eqn(1) is true, then derivatives of the lhs are also zero.
Define the coefficients ai
a = sym('a',[1 7]);
Define the test eqn and its derivatives
syms t
for ii = 0:6
eqn(ii+1) = diff(sum(a.*cos(t).^(0:6)),t,ii);
end
Put the set of equations into the form M*a = 0
[M,b] = equationsToMatrix(eqn,a); % b = 0
The only way this equation has a nonzero solution for a for all values of t is if M is singular for all t. Check the determinant
simplify(det(M))
ans = 
It is, in general, nonzero, so the only solution for all t that satisfies (1) is ai = 0. Therefore, the functions cos(t)^n (n=0:6) are linearly independent.

类别

在 Help Center 和 File Exchange 中查找有关 MATLAB 的更多信息

标签

产品


版本

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by