Is there a way to see and understand the steps of reduction while this equation gets solved for V? The result should be somewhere around 6. Thank you.

Question

Karl 2022-9-7

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https://ww2.mathworks.cn/matlabcentral/answers/1797455-is-there-a-way-to-see-and-understand-the-steps-of-reduction-while-this-equation-gets-solved-for-v-t

评论： Sam Chak 2022-9-7

(65-(50-V))/((15-V*0.5)/(V*0.866)) == ((50-V)-((65/(((15-V*0.5)/(V*0.866))+(1.363)))*(1.363)))/((((((((50*2-(50-V))/3.05)*1.732+(50-V))-(50-V))/((((((50*2-(50-V))/3.05)*1.732+(50-V))-(50-V))/((26.5)-(65-(50-V))/((28.4)/((26.5)-((28.4)/((15-V*0.5)/(V*0.866)))))))+1.732))*1.732+(50-V))-((65/(((15-V*0.5)/(V*0.866))+(1.363)))*(1.363)))/((26.86)-(((((((50*2-(50-V))/3.05)*1.732+(50-V))-(50-V))/((((((50*2-(50-V))/3.05)*1.732+(50-V))-(50-V))/((26.5)-(65-(50-V))/((28.4)/((26.5)-((28.4)/((15-V*0.5)/(V*0.866)))))))+1.732))*1.732+(50-V))-36.6)/((28.4)/((26.86)-((65-(50-V))/1.732)))))

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Answer 1

Sam Chak 2022-9-7

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编辑：Sam Chak 2022-9-7

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Hi @Karl

The equation is super long with many parentheses and it's hard to interpret without spaces. Maybe you can view it this way:

syms V

eqn = (65-(50-V))/((15-V*0.5)/(V*0.866)) == ((50-V)-((65/(((15-V*0.5)/(V*0.866))+(1.363)))*(1.363)))/((((((((50*2-(50-V))/3.05)*1.732+(50-V))-(50-V))/((((((50*2-(50-V))/3.05)*1.732+(50-V))-(50-V))/((26.5)-(65-(50-V))/((28.4)/((26.5)-((28.4)/((15-V*0.5)/(V*0.866)))))))+1.732))*1.732+(50-V))-((65/(((15-V*0.5)/(V*0.866))+(1.363)))*(1.363)))/((26.86)-(((((((50*2-(50-V))/3.05)*1.732+(50-V))-(50-V))/((((((50*2-(50-V))/3.05)*1.732+(50-V))-(50-V))/((26.5)-(65-(50-V))/((28.4)/((26.5)-((28.4)/((15-V*0.5)/(V*0.866)))))))+1.732))*1.732+(50-V))-36.6)/((28.4)/((26.86)-((65-(50-V))/1.732)))))

eqn =