Problem with exp() function

7 次查看（过去 30 天）
Joshua
Joshua 2022-9-8
评论： Stephen23 2022-9-8
Ran in:
I wonder why this function exp(1), which supposedly has to give you the Euler's constant, gives me the number 1. Furthermore, whenever I put a number bigger than 1, e.g., 3, it says that the index cannot exceed the number 1.
That is, the code is the following:
exp(1)
ans = 2.7183
But look at the following image:
It supposed to give me an approximation of Euler's constant.
Code Used:
exp(1)
>> ans = 1
exp(6)
Index exceeds the number of array elements. Index must not exceed 1.
Error in eulers_contant (line 2)
exp(6)
>>
I dont know what to do now.
  1 个评论
Stephen23
Stephen23 2022-9-8
"Problem with exp() function"
There is no problem with the EXP function.
"it says that the index cannot exceed the number 1."
You defined a scalar variable named EXP:
What do you expect to happen, when you try to access the 6th element of an array that only has one element?

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

David Hill
David Hill 2022-9-8
编辑：David Hill 2022-9-8
Ran in:
Make sure your clear your workspace and do not have any function names 'exp'
clear
format long
exp(1)
ans =
2.718281828459045
exp(6)
ans =
4.034287934927351e+02
  2 个评论
David Hill
David Hill 2022-9-8
You should not name variables as function names.
Walter Roberson
Walter Roberson 2022-9-8
Right, the image towards the left shows that the user had a variable named exp with a value of 1 as if they had coded
exp=(1)
instead of
exp(1)

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

产品


版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by