Adding polar plot to axes is not supported

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HYZ
HYZ 2022-9-8
评论： HYZ 2022-9-8
Hi,
The code works most of the time. sometimes, it showed error "Adding polar plot to axes is not supported" and I closed the matlab and ran again. Then it works for the same data.
Is there because there is a bug in Matlab when installation or the code is optimized. Please suggest. Thanks.
for i = 1: size (OSI,1)
if OSI (i) > 0.5
theta = 0 : pi/4: 2*pi;
p (i) = figure (i);
polarplot (theta, rho (i,:));
pax = gca;
thetaticks(0:45:315)
pax.ThetaDir = 'clockwise';
pax.ThetaZeroLocation = 'right';
pax.RTickLabel = []; %remove rho values inside polar plot
hlines = findall(gcf,'Type','line'); set(hlines,'LineWidth',3); %inside lines thicker
rl = rlim; hold on
polarplot([0 pi], rl(2)*[1 1], 'k--'); %connecting 0 and 180
polarplot([3*pi/2 pi/2], rl(2)*[1 1], 'k--'); %connecting 90 and 270
polarplot(linspace(0, 2*pi, 61), rl(2)*ones(61,1), 'k-', 'LineWidth', 2) %making border thicker
grid off;
title (sprintf('ROI %d: OSI %0.2f DSI %0.2f', i, OSI(i), DSI (i)))
cd(path_stim_all{itr})
saveas (gcf,strcat('ROI', '_', num2str(i), '_', 'OSI', '_', num2str (OSI(i)), 'DSI', '_', num2str (DSI(i)), '.jpeg'));
close all
end
end

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采纳的回答

Walter Roberson
Walter Roberson 2022-9-8
That error could potentially happen if figure(i) already exists and has a non-polar axis that already has "hold on" -- oh yes, and it would have to be i such that it is the first OSI(i) > 0.5 because you have the "close all" at the bottom.
You should probably not be creating a new figure each time; you should create a single figure before the loop and you should cla() each iteration, and get rid of the close all.

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