Central part of a matrix

1 次查看(过去 30 天)
Auryn_
Auryn_ 2015-2-24
Hello,
If a have a Matrix M and I want to create a new one, call it Central_M, which should be the central part of M and of a defined size s, how can I do it?
M_central = ?
Thanks in advance for your reply.
  2 个评论
Chris McComb
Chris McComb 2015-2-24
What exactly do you mean by 'central'? And can you define s?
Auryn_
Auryn_ 2015-2-25
Central means that I want to take only the central part of the matrix of a defined size s. s = imcrop(I,[max(1,i-10) max(1,j-10) 23 23]);

请先登录,再进行评论。

回答(2 个)

Jos (10584)
Jos (10584) 2015-2-25
Something like this?
M = spiral(10) % test matrix
S = 2 % s elements around the central position
% the resulting matrix will be 2*S+1 squared in size
dx = -S:S ;
RC0 = ceil(size(M)/2) % central position
OUT = M(RC0(1)+dx, RC0(2)+dx)

RAGHAVENDRA
RAGHAVENDRA 2015-2-25
编辑:Guillaume 2015-2-25
M_central=M(floor(size(M,1)/2)-floor(s/2):floor(size(M,1)/2)+floor(s/2),floor(size(M,2)/2)-floor(s/2):floor(size(M,2)/2)+floor(s/2));
The above instruction will work, you can use 'round' instead of 'floor' to change the matrix indices accordingly.
  3 个评论
Auryn_
Auryn_ 2015-2-25
I receive an error message :(
RAGHAVENDRA
RAGHAVENDRA 2015-2-25
编辑:RAGHAVENDRA 2015-2-25
It is working perfectly for me, this is the example that i have tried
M=randi(5,[10 10]);
s=2;
M_central=M(floor(size(M,1)/2)-floor(s/2):floor(size(M,1)/2)+floor(s/2),floor(size(M,2)/2)-floor(s/2):floor(size(M,2)/2)+floor(s/2))
What is the error message?

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by