print to screen with fromat

Question

Robert Jones 2022-9-10

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1802510-print-to-screen-with-fromat

评论： Star Strider 2022-9-10

Hello,

I am trying to print to screen results that come in the form of lines of numbers. I woul like to have the numbers aligned by the decimal dot.

I am using the following code

obj_str=[num2str(igor) '\t '  datestr(now) '\t'  num2str(x(:)','%15.3f') '\t'  num2str(qt,'%15.3f') '\n'];
fprintf(1,obj_str)

and I am getting the following output

1 10-Sep-2022 09:16:46 45.000 3.000 1.000 3.850 5.200 11.250 9.300 -0.042 18.456 51.792

2 10-Sep-2022 09:19:36 108.534 21.049 2.992 13.570 19.652 15.646 40.301 -0.004 4.129 26.957

3 10-Sep-2022 09:22:04 120.696 8.583 3.779 17.084 14.070 52.112 24.315 -0.295 -3.247 20.601

4 10-Sep-2022 09:24:52 81.327 20.654 4.337 18.853 22.594 16.111 23.815 -0.003 7.905 37.148

I would like to get an output simular to this

1 10-Sep-2022 09:16:46 45.000 3.000 1.000 3.850 5.200 11.250 9.300 -0.042 18.456 51.792

2 10-Sep-2022 09:19:36 108.534 21.049 2.992 13.570 19.652 15.646 40.301 -0.004 4.129 26.957

3 10-Sep-2022 09:22:04 120.696 8.583 3.779 17.084 14.070 52.112 24.315 -0.295 -3.247 20.601

4 10-Sep-2022 09:24:52 81.327 20.654 4.337 18.853 22.594 16.111 23.815 -0.003 7.905 37.148

any ideas?

Thank you

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Answer 1

Star Strider 2022-9-10

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1802510-print-to-screen-with-fromat#answer_1050765

在 MATLAB Online 中打开

Using only the posted data —

C = {1	 '10-Sep-2022 09:16:46'	45.000    3.000    1.000    3.850    5.200   11.250    9.300	-0.042   18.456   51.792
     2	 '10-Sep-2022 09:19:36'	108.534   21.049    2.992   13.570   19.652   15.646   40.301	-0.004    4.129   26.957
     3	 '10-Sep-2022 09:22:04'	120.696    8.583    3.779   17.084   14.070   52.112   24.315	-0.295   -3.247   20.601
     4	 '10-Sep-2022 09:24:52'	81.327   20.654    4.337   18.853   22.594   16.111   23.815	-0.003    7.905   37.148};
fileID = 1;
for k = 1:size(C,1)
    fprintf(fileID,['%d   %s ' repmat('%15.3f',1,10) '\n'], C{k,:})
end
1   10-Sep-2022 09:16:46          45.000          3.000          1.000          3.850          5.200         11.250          9.300         -0.042         18.456         51.792
2   10-Sep-2022 09:19:36         108.534         21.049          2.992         13.570         19.652         15.646         40.301         -0.004          4.129         26.957
3   10-Sep-2022 09:22:04         120.696          8.583          3.779         17.084         14.070         52.112         24.315         -0.295         -3.247         20.601
4   10-Sep-2022 09:24:52          81.327         20.654          4.337         18.853         22.594         16.111         23.815         -0.003          7.905         37.148