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read binary text from a file and add zeros to it

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Hadeel
Hadeel 2022-9-11
评论： Hadeel 2022-9-11
Please. I need to read binary text from a file and if it is not a multiple of a certain number, add zeros to te until it becomes a multiple of it,iam do tracing to my code and i discover that the statment a=......... in while loop donot change its value based on the new text,it remain on the first text.
text = fileread('text1.txt');
n=input('enter the length of segment: ');
a=mod(length(text),n);
if a~=0
while a~=0
text=string(text)+"0";
a=mod(length(text),n);
end
end

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采纳的回答

Image Analyst
Image Analyst 2022-9-11
You forgot to attach the file!
If the text is binary like 0s and 1s, maybe try this
b = logical(readmatrix('text1.txt'));
% Make the vector 500000 elements long by padding zeros.
b(5000000) = false;
If you have any more questions, then attach your data with the paperclip icon after you read this:
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更多回答（2 个）

Walter Roberson
Walter Roberson 2022-9-11
if a~=0
text = [text, repmat('0',1,n-a)];
end
Your bug is that you are converting text to string() array, but length() of a string array is the number of strings in the array, not the number of characters in the entry. See also strlength()
dpb
dpb 2022-9-11
移动：Image Analyst 2022-9-11
What's the form of the file -- just a string of 0s and 1s? if so then it would be simply something like
text = fileread('text1.txt');
N=input('enter the length of segment: ');
text=strcat(text,'0',repmat(1,N-strlength(text)));
if N > strlength(text), thanee it will add enough '0' to make up N overall; repmat will silengly do nothing if the repeat count is <=0 so you don't need any other logic outside; it's all handled internally ("magic happens").
fileread returns a char() vector to begin with so there's no conversion required there, either.

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