Find rows based on set of values/codes

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Millie Johnston
Millie Johnston 2022-9-13
评论： Star Strider 2022-9-14
Hello community,
I have a data set that is 48x14 (called data for this example). Each row has a set of codes (possible codes are 0 1 13 14 15 16 31 42 53 54). a row might look like this: [1 0 0 13 0 0 31 0 0 0 42 0 0 53].
The code is part of a for loop but I am strugglig with one specific part: I want to find rows that have a specific series of codes while ignoing the 0 codes. I thought the following code would work to find rows with the codes 1 13 31 42 and 53 in it:
for i = 1:length(data(:,1))
if all(data(i,find(data(i,:) == [1 13 31 42 53])))
.......
.......
I get the following error:
Arrays have incompatible sizes for this operation.
Any help would be much appreciated!

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采纳的回答

Star Strider
Star Strider 2022-9-13
Ran in:
I am not certain what you want, however the ismember function might be a better option than find for this, especially since everything seems to be integers, so no floating-point approximation problems will be present (requiring ismembertol and likely more coding) —
data = [1 0 0 13 0 0 31 0 0 0 42 0 0 53];
q = ismember(data, [1 13 31 42 53])
q = 1×14 logical array
1 0 0 1 0 0 1 0 0 0 1 0 0 1
v = data(q)
v = 1×5
1 13 31 42 53
Then determine what you want to do with either ‘q’ (using the nnz function could give the number of matches) or ‘v’ (the content of the matches in the vector) here.
.
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更多回答（2 个）

David Hill
David Hill 2022-9-13
for i = 1:size(data,2)
if all(ismember(data(i,:),[0 1 13 31 42 53]))%include 0
  2 个评论
Image Analyst
Image Analyst 2022-9-13
This answer doesn't care about the order of the desired sequence of codes you are looking for or if there are any duplicated numbers in the row.
My answer below requires that the sequence match exactly (not be scrambled or in arbitrary order like [13, 53, 42, 31, 1]).
We're not sure which way you want it, but now you have it both ways so you can choose.
Millie Johnston
Millie Johnston 2022-9-13
I am not looking for the sequnce per say, I am looking for the rows in which those numbers appear together (in any order). Does that make more sense?

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Image Analyst
Image Analyst 2022-9-13
Ran in:
Try this
oneRow = [1 0 0 13 0 0 31 0 0 0 42 0 0 53];
oneRow(oneRow == 0) = [] % Remove zeros
oneRow = 1×5
1 13 31 42 53
In addition you should be using isequal
% Define the specific sequence you are looking for.
desiredCodeSequence = [1 13 31 42 53]; % Row should be exactly this.
% See if it matches your zero-removed row.
if isequal(oneRow, desiredCodeSequence)
% Matched
fprintf('Matched.\n')
else
% The row is not the desired sequence.
fprintf('The row is not the desired sequence.\n')
end
Matched.

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