Different answers when I do the same integration

Hey,
I'm getting different answers when I perform the same integration but by just expanding the squared term.
How is this possible?
As I procced further, I'm getting 2 completely different answers as my result.
Which one is correct?
PS: I'm getting the same answer even after using 'IgnoreAnalyticConstraints',true.
Thanks

4 个评论

They don't look very similar:
X = linspace(0,pi,1e3);
Y1 = (1-cos(X)).^2;
Y2 = 1+cos(X).^2-2*(1-cos(X));
plot(X,Y1,X,Y2)
I have just used the identity (a-b)^2 = (a^2 + b^2 - 2ab). Technically, I should get the same results.
-2ab = -2*cos(n) and is not the same as -2*(1-cos(x))

请先登录,再进行评论。

回答(1 个)

They are not the same expressions.
syms x
int((1+cos(x))^2,0,pi)
ans = 
int(1+2*cos(x)+cos(x)^2,0,pi)
ans = 
int(1+cos(x)^2-2*(1-cos(x)),0,pi)%this is not the same expression
ans = 

2 个评论

My bad, added the wrong screenshot. please try int((1-cos(x))^2,0,pi).
I did not get the same answer with that. (please check the updated screenshot)
Look up the binomial formula:
(a-b)^2 = a^2 - 2*a*b + b^2

请先登录,再进行评论。

类别

帮助中心File Exchange 中查找有关 Numerical Integration and Differentiation 的更多信息

产品

版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by