Using parfor for reflection function

Question

Aknur 2022-9-14

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1804895-using-parfor-for-reflection-function

评论： Aknur 2022-9-19

Hi! I have light rays and their points (x0, y0, z0; x1, y1, z1; ) I want to apply parfor for calculation of reflection (x, y, z) for each point, and for end point (x, y, z ). Reflection points (x, y, z) of the first reflection will be the starting point for the next one, and so on. I am really absolutely new in Matlab. Here is my draft. And also I will calculate length of the ray (using Pythagorean theorem) Thank you for your help in advance

function [x,y,z] = reflection(x0, y0, z0, theta ... )

% Detailed explanation goes here

outputArg1 = inputArg1;

outputArg2 = inputArg2;

end

% number of reflection

Bk = 6;

parfor ii=1:Bk;

for ii = 1:5

x(ii), y(ii), z(ii) = reflection(x0,y0,z0, theta(ii))

length of the ray (using Pythagorean theorem)

% Ray1 1.5, 0 ,0

x0 = 1.5;

x1 = 1.5;

y0 = 1.5;

y1 = 0;

z0 = 3;

z1 = 0;

% length of ray

d1 = sqrt((x1-x0)^2 + (y1-y0)^2 + (z1-z0)^2);

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2022-9-14

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1804895-using-parfor-for-reflection-function#answer_1053105

You define a function. Inside the function you use parfor. Inside the function you call itself recursively. That would attempt to invoke parfor within the existing parfor, which is permitted but would treat the inner parfor as a plain for loop.

You do not have any termination test on your recursion so the function is going to invoke itself over and over again until you exceed the stack limit and generate an error.