Fast Look-up table

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T
T 2015-2-26
回答： dpb 2015-2-26
Good morning, I have a long array signal with values x. Now for each of those values x I want to find the closest fit in another array pvalues and return the index. At the moment I am doing it like this:
for a=1:1:length(signal)
tempp=pvalues-abs(signal(a));
[c index1] = min(abs(tempp));
%do stuff with index1
end
But this takes a lot of time (hours)! If I comment all lines and only iterate through the array signal, it is done in 3 seconds. So the problem is finding the index1 value.
Any ideas how to solve this quickly?
Thank you!

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回答（1 个）

dpb
dpb 2015-2-26
[~,idx]=min(pdist2(pvalues,abs(signal),'euclidean'));

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