[~,idx]=min(pdist2(pvalues,abs(signal),'euclidean'));
Fast Look-up table
2 次查看(过去 30 天)
显示 更早的评论
Good morning, I have a long array signal with values x. Now for each of those values x I want to find the closest fit in another array pvalues and return the index. At the moment I am doing it like this:
for a=1:1:length(signal)
tempp=pvalues-abs(signal(a));
[c index1] = min(abs(tempp));
%do stuff with index1
end
But this takes a lot of time (hours)! If I comment all lines and only iterate through the array signal, it is done in 3 seconds. So the problem is finding the index1 value.
Any ideas how to solve this quickly?
Thank you!
0 个评论
回答(1 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!