Data plot for different values

2022 9 14
1 个回答
回答已采纳
更新时间：2022 9 14
4 次查看（30 天）

0 个投票

I want plot theta as a function of z at t = time(nt) for all xi values but receive: Error using plot: Data cannot have more than 2 dimensions om line 140.

请先登录，再回答此问题。

 采纳的回答

Torsten
Torsten 2022-9-14

0 个投票

%store your outputs for each xi
thetaxivalues(ixi,:,:) = theta(:,:);
vxivalues(ixi,:,:) = v(:,:);
What is ixi ? I guess, it's a single scalar, namely ixi = nxi from the last loop where ixi appears:
for ixi = 1:length(xivalues)
xi = xivalues(ixi);
end
So you don't store outputs for each xi.

8 个评论
显示 6更早的评论 隐藏 6更早的评论

University Glasgow
University Glasgow 2022-9-14
I actually wants the xi to take values from xivalues = linspace(-0.3, -0.1, nxi).
Torsten
Torsten 2022-9-14
But your vector "theta" does not depend on xi.
So it makes no sense to set
thetaxivalues(1:nxi,:,:) = theta(:,:);
vxivalues(1:nxi,:,:) = v(:,:);
because every vector thetaxivalues and vxivalues will contain the same values for 1 <= ixi <= nxi.
University Glasgow
University Glasgow 2022-9-14
You are right but what do you suggest then?
Torsten
Torsten 2022-9-14
Your simulations must contain xi as a parameter and you must vary this parameter to get theta(xi,:,:) and v(xi,:,:).
University Glasgow
University Glasgow 2022-9-14
Please, could you help me out.
Torsten
Torsten 2022-9-14
编辑：Torsten 2022-9-14
How could I ?
I don't know anything about your model, and at the moment, I don't see a variable xi within the equations in lcode1 that could be varied.
University Glasgow
University Glasgow 2022-9-14
If you cehck the discretised equations, I have xi in the v equation.
Please check, you will see: (xi/(2*h))*(theta(N-1)-theta(N-3));
Torsten
Torsten 2022-9-14
编辑：Torsten 2022-9-14
Then call the solver in a loop over the elements of xi and write the results in a 3d v and theta array.
But that's really standard and I won't do that for you.

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 MATLAB 的更多信息

产品

版本

R2022a

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by