Conversion of linear equations to form Ax=b
2 次查看(过去 30 天)
显示 更早的评论
Hello everyone,
I have the following equations:
syms t u v w x y z
intersection_a = -t + w + x == 100;
intersection_b = t - u == 100;
intersection_c = v + w - y - z == 0;
intersection_d = u + v == 40;
I can convert it to form of Ax=b using equationsToMatrix(). But my question is if I have t = 100 and w+x+y = 100, then does the equation change? Do I need to put t = 100 etc in these equations? If I will, then there will be no t in equations. How I will be able to write then it in form of Ax= b where x = [t u v w x y z] '?
Thanks in advance.
0 个评论
采纳的回答
Sam Chak
2022-9-15
You have only 4 equations, but there are 6 unknowns. So, the linear system is clearly rank-deficient.
syms t u v w x y z
t = 100;
intersections = [-t + w + x == 100, ...
t - u == 100, ...
v + w - y - z == 0, ...
u + v == 40];
vars = [u, v, w, x, y, z];
[A, b] = equationsToMatrix(intersections, vars)
x = linsolve(A, b)
6 个评论
Torsten
2022-9-15
If it has to be satisfied, it has to be included. Why do you ask for this specific equation ? Is it different from the others ?
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Numbers and Precision 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!