Inserting an array in another to make an Nested Array

Hello I want to build a fractal. I want to start with One=[1 0 1;0 0 0;1 0 1] Zero=zeros(3)
Then I want to search this array for an element =1 if equal to "1" insert the array One otherwise the array Zero. I am pretty sure this can be done with Cat but wanted to see what others think.
Thanks for your time.

2 个评论

Please provide a complete example of inputs and desired output. "insert the array" really doesn't tell us much about what you really want.
Hmmm. OK let me try again. My generator array is called "One" One= [1 0 1;0 0 0;1 0 1];
The next level fractal is where One is inserted in every element of "One" where "1" exists. If the element contains a "0" then the array Zero is inserted into One. Zero=zero(3); I am simply looking for a simple way to nest One and Zero into my generator array.

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 采纳的回答

C = {zeros(3); [1 0 1; 0 0 0; 1 0 1]};
X = [1 1 0; 0 1 0]; %current matrix
X = cell2mat(C(X+1)) %new matrix

2 个评论

Can you help me understand how cell2mat used in this way works? How does cell2mat interpret C(X+1)?
It's fairly basic indexing, Y = C(X) returns an array Y the size of X (*) where each element Yn is the value of C at index Xn.
Therefore, in C(X+1), when Xn == 0, Yn is C(1) and when Xn == 1, Yn is C(2).
* except under some circumstances (both are vectors) because people at Mathworks love having exceptions which we all know makes generic programming so much easier. /end rant

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更多回答(1 个)

ONE = [1 0 1;0 0 0;1 0 1];
M = (your current matrix of 1's and 0's)
M = kron(M,ONE); % This will be the next version of M

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