Iterating through a dataset and creating a vector with according values

3 次查看(过去 30 天)
So I have a 10 000 X 1 vector (let's call it vector A) of different values ranging from -1 to 1. I want to create another 10 000 X 1 vector (let's call it vector B) that has values corresponding to the ones in the first vector. I want to create a loop that does this:
Everytime a value in vector A is bigger than 0.5, add the value 3 to vector B with the same corresponding position.
Everytime a value in vector A is smaller than -0.5, add the value 1 to vector B with the same corresponding position.
Everytime a value in vector A is between -0.5 and 0.5, add the value 2 to vector B with the same corresponding.
In that case, the resulting matrix should look like this:
[A] [B]
-0.9 1
-0.3 2
0.6 3
-0.2 2
-0.7 1
I know I need to use a loop but I struggle with this. Thank you so much for your help.

回答(1 个)

dpb
dpb 2022-9-20
Rarely need loops for such things as this with MATLAB; either logical addressing or table lookup almost always comes to the rescue -- the latter (using the builtin interpolation routine) solution here would be
A=[-0.9;-0.3;0.6;-0.2;-0.7];
B=interp1([-1,-0.5,0.5,1],[1,2,3,3],A,'previous')
B = 5×1
1 2 3 2 1
Alternatively, another lookup solution, with less overhead...
B=discretize(A,[-1,-0.5,0.5,1])
B = 5×1
1 2 3 2 1
  4 个评论
Dyuman Joshi
Dyuman Joshi 2022-9-20
After you get the values, you can get the values as such
str={'GT';'IN';'ST'};
A=[-0.9;-0.3;0.6;-0.2;-0.5;0.5];
B=interp1([-1,-0.5,0.5,1],[1,2,3,3],A,'previous');
%cell array
C=str(B)
C = 6×1 cell array
{'GT'} {'IN'} {'ST'} {'IN'} {'IN'} {'ST'}
%char array
D=cell2mat(C)
D = 6×2 char array
'GT' 'IN' 'ST' 'IN' 'IN' 'ST'
dpb
dpb 2022-9-20
编辑:dpb 2022-9-20
If the border edge cases are that important, use bkpt-eps(bkpt) to add the necessary granularity in either solution.
There are multiple other answers I've posted (at least one pretty recently) that illustrate...

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Startup and Shutdown 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by