how can I find the intersection of two surface

1 次查看(过去 30 天)
Hi, I wrote the code below to find the intersection of two surfaces "cdot: and "ctdot", but it has an error : Z must be a matrix, not a scalar or vector.
Could you please tell me how solve it, thanks for any help.
vplc=0.16;
delta=0.1;
Ktau=0.045;
Kc=0.1;
K=0.0075;
Kp=0.15;
gamma=5.5;
Kb=0.4;
alpha0=delta*6.81e-6/(0.002);
alpha1=delta*2.27e-5/(0.002);
Ke=7;
Vs=0.002;
Ks=0.1;
Kf=0.18;
kplc=0.055;
ki=2;
tau_max=0.176;
Vss=0.044;
A=(-(Vss.*c.^2)./(Ks.^2))+((Vs.*K.*gamma.^2.*ct.^2)./(Ks.^2))+alpha0+alpha1.*((Ke.^4)./(Ke.^4+(gamma.*ct).^4));
p=(vplc.*c.^2./(c.^2+kplc.^2))./ki;
h=(-(0.4.*A.*((Kc.^4).*(Kp.^2))./((p.^2.*c.^2.*gamma.*ct.*Kf))));
G1=alpha0+(alpha1.*Ke.^4./((gamma.*ct).^4+Ke.^4));
G2=((1-h)./tau_max).*c.^4;
Fc=(4.*gamma.*Kf).*((c.^3.*p.^2.*h.*ct)./(Kb.*Kp.^2.*Ktau.^4))-(2.*Vss.*c./Ks.^2);
Fct=((gamma.*Kf.*(c.^4).*(p.^2).*h)./(Kb.*Kp.^2.*Ktau.^4))+((Vs.*K.*gamma.^2)./(Ks.^2))-((4.*gamma.^4.*ct.^3.*alpha1.*Ke.^4)./(Ke.^4+(gamma.*ct).^4).^2);
Fh=(gamma.*Kf.*c.^4.*p.^2.*ct)./(Kb.*Kp.^2.*Ktau.^4);
cdot=@(ct,c)(((gamma.*Kf.*(c.^4).*(p.^2).*h)./(Kb.*Kp.^2.*Ktau.^4))+((Vs.*K.*gamma.^2)./(Ks.^2))-((4.*gamma.^4.*ct.^3.*alpha1.*Ke.^4)./(Ke.^4+(gamma.*ct).^4).^2)).*(alpha0+(alpha1.*Ke.^4./((gamma.*ct).^4+Ke.^4)))+((gamma.*Kf.*c.^4.*p.^2.*ct)./(Kb.*Kp.^2.*Ktau.^4)).*(((1-h)./tau_max).*c.^4);
ctdot=@(ct,c)(-(alpha0+(alpha1.*Ke.^4./((gamma.*ct).^4+Ke.^4))).*((4.*gamma.*Kf).*((c.^3.*p.^2.*h.*ct)./(Kb.*Kp.^2.*Ktau.^4))-(2.*Vss.*c./Ks.^2)));
ct = 0:.1:2.5;
c = 0:.1:2.5;
[Ct,C] = meshgrid(ct,c);
figure
surf(Ct,C,cdot(Ct,C)-ctdot(Ct,C))
hold on
contour3(C,Ct,cdot(Ct,C)-ctdot(Ct,C), [0 0], '-r', 'LineWidth',2)

采纳的回答

Star Strider
Star Strider 2022-9-20
编辑:Star Strider 2022-9-20
MATLAB is case-sensitive so ‘ct’ ~= ‘Ct’ (and so for the others) in the ‘cdot’ and ‘ctdot’ calls.
I would like to run this to demonstrate that, however ‘c’ is nowhere to be found.
vplc=0.16;
delta=0.1;
Ktau=0.045;
Kc=0.1;
K=0.0075;
Kp=0.15;
gamma=5.5;
Kb=0.4;
vss=0.044;
alpha0=delta*6.81e-6/(0.002);
alpha1=delta*2.27e-5/(0.002);
Ke=7;
Vs=0.002;
Ks=0.1;
Kf=0.18;
kplc=0.055;
ki=2;
tau_max=0.176;
Vss=0.044;
ct = 0:.1:2.5;
c = 0:.1:2.5;
A=(-(vss.*c.^2)./(ks.^2))+((Vs.*K.*gamma.^2.*ct.^2)./(ks.^2))+alpha0+alpha1.*((Ke.^4)./(Ke.^4+(gamma.*ct).^4));
Unrecognized function or variable 'ks'.
p=(vplc.*c.^2./(c.^2+kplc.^2))./ki;
h=(-(0.4.*A.*((Kc.^4).*(Kp.^2))./((p.^2.*c.^2.*gamma.*ct.*Kf))));
G1=alpha0+(alpha1.*Ke.^4./((gamma.*ct).^4+Ke.^4));
G2=((1-h)./tau_max).*c.^4;
Fc=(4.*gamma.*Kf).*((c.^3.*p.^2.*h.*ct)./(Kb.*Kp.^2.*Ktau.^4))-(2.*Vss.*c./Ks.^2);
Fct=((gamma.*Kf.*(c.^4).*(p.^2).*h)./(Kb.*Kp.^2.*Ktau.^4))+((Vs.*K.*gamma.^2)./(Ks.^2))-((4.*gamma.^4.*ct.^3.*alpha1.*Ke.^4)./(Ke.^4+(gamma.*ct).^4).^2);
Fh=(gamma.*Kf.*c.^4.*p.^2.*ct)./(Kb.*Kp.^2.*Ktau.^4);
cdot=@(ct,c)(((gamma.*Kf.*(c.^4).*(p.^2).*h)./(Kb.*Kp.^2.*Ktau.^4))+((Vs.*K.*gamma.^2)./(Ks.^2))-((4.*gamma.^4.*ct.^3.*alpha1.*Ke.^4)./(Ke.^4+(gamma.*ct).^4).^2)).*(alpha0+(alpha1.*Ke.^4./((gamma.*ct).^4+Ke.^4)))+((gamma.*Kf.*c.^4.*p.^2.*ct)./(Kb.*Kp.^2.*Ktau.^4)).*(((1-h)./tau_max).*c.^4);
ctdot=@(ct,c)(-(alpha0+(alpha1.*Ke.^4./((gamma.*ct).^4+Ke.^4))).*((4.*gamma.*Kf).*((c.^3.*p.^2.*h.*ct)./(Kb.*Kp.^2.*Ktau.^4))-(2.*Vss.*c./Ks.^2)));
% ct = 0:.1:2.5;
% c = 0:.1:2.5;
[Ct,C] = meshgrid(ct,c);
figure
surf(Ct,C,cdot(Ct,C)-ctdot(Ct,C))
hold on
contour3(C,Ct,cdot(Ct,C)-ctdot(Ct,C), [0 0], '-r', 'LineWidth',2)
.
  17 个评论
Torsten
Torsten 2022-9-23
At least cdot(ct,c) = 0 is empty for ct >=0.
ctdot(ct,c) = 0 gives two implicit curves symmetric to the ct-axis.
Star Strider
Star Strider 2022-9-23
Originally, the objective was to determine the intersection:
figure
surf(Ct,C,cdot(Ct,C)-ctdot(Ct,C))
hold on
contour3(C,Ct,cdot(Ct,C)-ctdot(Ct,C), [0 0], '-r', 'LineWidth',2)
I am not certain where we are at this point.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Contour Plots 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by