partial differential for nonlinear equation

i want the partial differential of this equation w.r.t X , Y and Z
31.65951=sqrt((20460991.052399-X)^2+(11012393.207537-Y)^2+(13140061.841029-Z)^2)-sqrt((20462649.31-X)^2+(11012196.356-Y)^2+(13137623.266-Z)^2)

 采纳的回答

Use gradient
syms X Y Z
Eq = -31.65951 + sqrt((20460991.052399-X)^2+(11012393.207537-Y)^2+(13140061.841029-Z)^2)-sqrt((20462649.31- X)^2+(11012196.356-Y)^2+(13137623.266-Z)^2);
gradient(Eq)
ans =
(2*X - 5492455463362645/134217728)/(2*((Z - 3527258492164819/268435456)^2 + (X - 5492455463362645/268435456)^2 + (Y - 2956116792316497/268435456)^2)^(1/2)) - (2*X - 5492900598497935/134217728)/(2*((Z - 7053207784329839/536870912)^2 + (X - 5492900598497935/268435456)^2 + (Y - 5912127900768797/536870912)^2)^(1/2))
(2*Y - 2956116792316497/134217728)/(2*((Z - 3527258492164819/268435456)^2 + (X - 5492455463362645/268435456)^2 + (Y - 2956116792316497/268435456)^2)^(1/2)) - (2*Y - 5912127900768797/268435456)/(2*((Z - 7053207784329839/536870912)^2 + (X - 5492900598497935/268435456)^2 + (Y - 5912127900768797/536870912)^2)^(1/2))
(2*Z - 3527258492164819/134217728)/(2*((Z - 3527258492164819/268435456)^2 + (X - 5492455463362645/268435456)^2 + (Y - 2956116792316497/268435456)^2)^(1/2)) - (2*Z - 7053207784329839/268435456)/(2*((Z - 7053207784329839/536870912)^2 + (X - 5492900598497935/268435456)^2 + (Y - 5912127900768797/536870912)^2)^(1/2))

3 个评论

error
syms X Y Z Eq = -31.65951 + sqrt((20460991.052399-X)^2+(11012393.207537-Y)^2+(13140061.841029-Z)^2)-sqrt((20462649.31- X)^2+(11012196.356-Y)^2+(13137623.266-Z)^2); gradient(Eq) ??? Error using ==> zeros Trailing string input must be a valid numeric class name.
Error in ==> gradient at 64 g = zeros(size(f),class(f)); % case of singleton dimension
Ahmed, how are you running these lines of code? Within a script/function?
Can you get it to run in the MATLAB command window?
thanks for your reply > but i want the version of you matlab to solve the above function gradient

请先登录,再进行评论。

更多回答(0 个)

类别

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by