How to calculate and sketch the Fourier Transform of a gaussian function?

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Hello,
I have the following function:
(exp(-pi.*x.^2) + 0.25.*exp((-pi.*x.^2)/16))
Unrecognized function or variable 'x'.
I'm trying to calculate and sketch its fourier transform version.
This is what I tried but it seems wrong.
x_fit_func = @(x) (exp(-pi.*x.^2) + 0.25.*exp((-pi.*x.^2)/16));
x = linspace(-10, 10, 50);
x_F = fft(x_fit_func(x))/numel(x);
Fs = 1/mean(diff(x));
Fn = Fs/2;
Fv = linspace(-1, 1, numel(x_F))*Fn;
Iv = 1:numel(Fv);
figure
plot(Fv, fftshift(abs(x_F)))
grid

采纳的回答

Paul
Paul 2022-9-22
Hi Steven
What doesn't seem correct? The only issue I see is the calculation of Fv, modified below.
x_fit_func = @(x) (exp(-pi.*x.^2) + 0.25.*exp((-pi.*x.^2)/16));
x = linspace(-10, 10, 50);
x_F = fft(x_fit_func(x))/numel(x);
Fs = 1/mean(diff(x));
Fv = (-25:24)/50*Fs; % frequency vector for N = 50 (N is even)
figure
plot(Fv, fftshift(abs(x_F)))
grid
  2 个评论
Nathan
Nathan 2022-9-22
I'm still new to matlab and read this code from another forum, which is why I'm not so sure if the impulse response looks correct. I initially tried fft(f_x) where f_x is my function in time domain but the graph came out looking very weird. Do you mind explain your code briefly? Thank you!
Paul
Paul 2022-9-22
I'm not sure how impulse response has entered the dicussion or what fft(f_x) means without seeing a definition of f_x.
My code is your code. All I did was correct the calculation of the Fv vector. Is that the part that needs further explanation?

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