How to terminate the MATLAB code?
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I'm running the following code
n = 10000000;
a = 3.8;
x(1) = 0.5;
tic
for i=1:n
x(i+1)=a*x(i)*(1-x(i));
end
Time = toc
I wanted to set some time limit say Time = 35 s.
How can I apply time limit condition on the above code such that if Time= 35 s. The code will automatically terminate.
1 个评论
Sharmin Kibria
2022-9-23
You can move Time=toc inside the loop and break if (Time == 35) .
采纳的回答
n = 100000000;
a = 3.8;
x(1) = 0.5;
tic
Time = 0;
for i=1:n
if Time > 5
fprintf('You run out of time')
break
end
x(i+1)=a*x(i)*(1-x(i));
Time = toc;
end
disp(Time)
2 个评论
Noor Fatima
2022-9-23
Walter Roberson
2022-9-23
In order to impose a time limit on a calculation without the cooperation of the code, you have to use parfeval() to run the code in a parallel pool or in a background thread pool; you can cancel() the "future" of the worker if it reaches the time limit.
Background pools were introduced relatively recently and do not require additional toolboxes. Parallel pools are older but require Parallel Computing Toolbox
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