How to terminate the MATLAB code?

3 次查看（过去 30 天）
Noor Fatima
Noor Fatima 2022-9-23
评论： Walter Roberson 2022-9-23
I'm running the following code
n = 10000000;
a = 3.8;
x(1) = 0.5;
tic
for i=1:n
x(i+1)=a*x(i)*(1-x(i));
end
Time = toc
I wanted to set some time limit say Time = 35 s.
How can I apply time limit condition on the above code such that if Time= 35 s. The code will automatically terminate.

请先登录，再回答此问题。

采纳的回答

Davide Masiello
Davide Masiello 2022-9-23
Ran in:
n = 100000000;
a = 3.8;
x(1) = 0.5;
tic
Time = 0;
for i=1:n
if Time > 5
fprintf('You run out of time')
break
end
x(i+1)=a*x(i)*(1-x(i));
Time = toc;
end
You run out of time
disp(Time)
5.0000
  2 个评论
Noor Fatima
Noor Fatima 2022-9-23
@Davide Masiello Thank you,
If there is not a for loop , can we apply time limit ?
e.g.,
tic
X = myfunction(a, n,x)
toc
Walter Roberson
Walter Roberson 2022-9-23
In order to impose a time limit on a calculation without the cooperation of the code, you have to use parfeval() to run the code in a parallel pool or in a background thread pool; you can cancel() the "future" of the worker if it reaches the time limit.
Background pools were introduced relatively recently and do not require additional toolboxes. Parallel pools are older but require Parallel Computing Toolbox

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by