How to terminate the MATLAB code?

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Noor Fatima
Noor Fatima 2022-9-23
评论： Walter Roberson 2022-9-23
I'm running the following code
n = 10000000;
a = 3.8;
x(1) = 0.5;
tic
for i=1:n
x(i+1)=a*x(i)*(1-x(i));
end
Time = toc
I wanted to set some time limit say Time = 35 s.
How can I apply time limit condition on the above code such that if Time= 35 s. The code will automatically terminate.

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采纳的回答

Davide Masiello
Davide Masiello 2022-9-23
Ran in:
n = 100000000;
a = 3.8;
x(1) = 0.5;
tic
Time = 0;
for i=1:n
if Time > 5
fprintf('You run out of time')
break
end
x(i+1)=a*x(i)*(1-x(i));
Time = toc;
end
You run out of time
disp(Time)
5.0000
  2 个评论
Noor Fatima
Noor Fatima 2022-9-23
@Davide Masiello Thank you,
If there is not a for loop , can we apply time limit ?
e.g.,
tic
X = myfunction(a, n,x)
toc
Walter Roberson
Walter Roberson 2022-9-23
In order to impose a time limit on a calculation without the cooperation of the code, you have to use parfeval() to run the code in a parallel pool or in a background thread pool; you can cancel() the "future" of the worker if it reaches the time limit.
Background pools were introduced relatively recently and do not require additional toolboxes. Parallel pools are older but require Parallel Computing Toolbox

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