I'm new in using Matlab and I'm very confused of how I would solve a derivative problem. Here is the equations and problem

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Neil Allen
Neil Allen 2022-9-24
评论： Davide Masiello 2022-9-24

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Hiro Yoshino
Hiro Yoshino 2022-9-24
Ran in:
You are using the capabilities of Symbolic Math Toolbox and with this you can manupulate your equations symbolically.
Let's define your symbol x. Then the following equation y1 is also defined symbolically as follows:
syms x a
y1(x) = 1/((x+1)^3*(2*x-1)^3) + a
y1(x) = 
Derivative of y1 is quite straightfoward. If you want to differentiate y1 with respect to x, diff is the one:
yp1 = diff(y1)
yp1(x) = 
If you want to know the variables used in the function y1, symvar will do the work
symvar(y1)
ans = 
x

更多回答（1 个）

Davide Masiello
Davide Masiello 2022-9-24
编辑：Davide Masiello 2022-9-24
Ran in:
I think what you have in your snapshot is already ok. You just need to save the functions in y1, y2 and y3. There are also some errors with the brackets, check your code carefully.
syms x
y1(x) = 1/((x+1)^3*(2*x-1)^3);
y2(x) = 1/(1+sqrt(1-x))^3;
y3(x) = (x^2/(4-x))^(3/2);
yp1 = diff(y1)
yp1(x) = 
yp2 = diff(y2)
yp2(x) = 
yp3 = diff(y3)
yp3(x) = 

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