Rect function with Array

13 次查看(过去 30 天)
kale
kale 2022-9-24
编辑: Matt J 2022-9-24
I would like to write my Rect function and I declared the following input variables:
A = 2; %amplitude
T0 = 3; %period
t = [0:Ts:T0]; %time vector base (Ts = 0.01 = time sampling)
The function I wrote is as follows:
function [y] = rect(T0, A, t)
if t < -T0/2
y = 0;
elseif ((t >= -T0/2) & (t <= T0/2))
y = amplitude;
else y = 0; %if t > T0/2
end
I think the problem is the comparison (in the if and elseif) of the vector t with the scalar T0/2, in fact by putting a breakpoint I seem to have noticed that the comparison of the if is only performed on the first element of t (i.e. 0) .. and not with all the others.
I am asking you to suggest the right syntax to use and also (possibly) tell me if I have got the reasoning behind this function wrong.
I thought of doing a for (or while) loop inside the rect function where I increment t=t+Ts, but I would like to avoid this by using the vector t already declared incremented by Ts (as I did)
Thanks!

采纳的回答

Matt J
Matt J 2022-9-24
编辑:Matt J 2022-9-24
function [y] = rect(T0, A, t)
y= ((t >= -T0/2) & (t <= T0/2)) * A;
end
  2 个评论
kale
kale 2022-9-24
Thank you.
What if I want a train of pulses (rectangular) ?
How do you modify your function ?
Matt J
Matt J 2022-9-24
编辑:Matt J 2022-9-24
You can use the function to create several pulses and add them together.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Language Fundamentals 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by