How To change Diagonal Elements with a string in matrix using FOR loop or other preferred method?

Question

Faisal 2022-9-24

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1811420-how-to-change-diagonal-elements-with-a-string-in-matrix-using-for-loop-or-other-preferred-method

回答： David Hill 2022-9-24

the result is to have a square matrix with a string e.g. "A" as diagonal elements using FOR LOOP

example:

M =

A 0 0 0 0

0 A 0 0 0

0 0 A 0 0

0 0 0 A 0

0 0 0 0 A

or How can I Print my name like ALEX diagonally

example;

M =

A 0 0 0

0 L 0 0

0 0 E 0

0 0 0 X

Here is My code that gives a specific number I assigned to variable in loop; however when that number is replaced with string it results NAN value as Diagonal elements.

clc
clear
clear all
m=5;
n=5;
a=zeros(m,n);
for i=1:m
    for j=1:n
        if i==j
a(i,j)= 5 ;
        else
            a(i,j)=0;
            
        end
    end
end
disp(a)
     5     0     0     0     0
     0     5     0     0     0
     0     0     5     0     0
     0     0     0     5     0
     0     0     0     0     5
clc
clear
clear all
m=5;
n=5;
a=zeros(m,n);
for i=1:m
    for j=1:n
        if i==j
a(i,j)= "A" ;
        else
            a(i,j)=0;
            
        end
    end
end
disp(a)
   NaN     0     0     0     0
     0   NaN     0     0     0
     0     0   NaN     0     0
     0     0     0   NaN     0
     0     0     0     0   NaN

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Turlough Hughes 2022-9-24

You can't mix characters or string values into an array of type double like that. On the otherhand, you can atleast represent numbers in a string array. Seeing as this is an exercise, I'm just going to nudge you towards a solution. Try starting with the following:

a = string(zeros(5))
a = 5×5 string array
    "0"    "0"    "0"    "0"    "0"
    "0"    "0"    "0"    "0"    "0"
    "0"    "0"    "0"    "0"    "0"
    "0"    "0"    "0"    "0"    "0"
    "0"    "0"    "0"    "0"    "0"

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Answer 1

David Hill 2022-9-24

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1811420-how-to-change-diagonal-elements-with-a-string-in-matrix-using-for-loop-or-other-preferred-method#answer_1060005

a='ALEX';
b=diag(double(a));
b(b==0)=48;
string(char(b))
ans = 4×1 string array
    "A000"
    "0L00"
    "00E0"
    "000X"
char(b)
ans = 4×4 char array
    'A000'
    '0L00'
    '00E0'
    '000X'