Index out of bounds

Question

Dee Tress 2015-3-3

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评论： Dee Tress 2015-3-3

I am trying to use the patient number inputed into the filename to access the correct body information. There are 4 patients and each has 8 related properties. When I define which patient number it is from the filename, it brings up the correct number, and when I use that number manually to define the index in tbw the code works fine. But when I use the variable name, it somehow uses a different value for 'patientno' (its actually adding 48 to the value. e.g. patient 2 tries to index 50)

Here is my code:

patientno = filename(2);
patientstats = zeros(4,8);
patientstats(1:4,1:8) = [860.0,75.7,39.1,9.2,174.0,43.3,38.1,30.0; 702.0,62.2,36.5,9.9,165.0,39.3,40.0,29.0; 800.0,98.4,43.0,7.2,170.0,47.5,40.9,26.0; 980.0,80.2,53.9,12.3,175.0,41.0,41.0,27.5];
%Define individual anthropometric information 
tbw = patientstats(patientno,1)
tw = patientstats(patientno,2);

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Answer 1

Andrew Newell 2015-3-3

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编辑：Andrew Newell 2015-3-3

在 MATLAB Online 中打开

The variable name filename is probably char, not numeric. Suppose you define

filename = '12';

Then if you view the second character in the name, you see:

filename(2)
ans =
   2

But if you try to use it as an index, it uses the ASCII number of the character, and that is:

double(filename(2))
ans =
    50

So what you need to do is define patientno using

patientno = str2num(filename(2));

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Dee Tress 2015-3-3

Thank you, this worked perfectly

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Answer 2

Joseph Cheng 2015-3-3

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https://ww2.mathworks.cn/matlabcentral/answers/181324-index-out-of-bounds#answer_169960

From what i see filename is probably a string, so what you're doing is trying to access patientstats('2',1) and patientstats('2',2), which '2' is an ascii character which has the decimal equivalent of 50. you'll need to use str2num(patientno) to convert it to decimal.