Receiving Matrix Dimensions Do Not Agree Error

1 次查看(过去 30 天)
My MatLab script is:
R3=100; R4=2000; R5=50; R6=4000; R7=5000; V1=5; V2=3; I8=.008;
A= [0 0 0 0 0 0 0 1 -1 0 0 0 0; 0 0 0 0 0 0 0 0 0 0 0 1 -1; 0 0 0 0 0 0 -1 0 0 0 1 0 0; 0 0 0 0 0 0 1 0 0 0 0 -1 0; 0 0 0 0 0 0 0 0 1 -1 0 0 1; 0 0 1 1 0 1 0 0 0 0 0 0 0; -1 0 0 0 1 -1 0 0 0 0 0 0 0; 0 -1 0 -1 -1 0 0 0 0 0 0 0 0; 1 0 0 0 0 0 0 0 -R3 0 0 0 0; 0 1 0 0 0 0 0 0 0 -R4 0 0 0; 0 0 1 0 0 0 0 0 0 0 -R5 0 0; 0 0 0 1 0 0 0 0 0 0 0 -R6 0; 0 0 0 0 1 0 0 0 0 0 0 0 -R7];
Y= [0 I8 0 0 0 -V1 V2 0 0 0 0 0 0];
X=inv(A)*Y;
I have checked the dimensions over and over again and they appear to agree. What am I doing wrong?

采纳的回答

Shoaibur Rahman
Shoaibur Rahman 2015-3-4
Instead of Y use Y transpose as Y' in the last line of your code.
X=inv(A)*Y'
However if you use the following line instead, it will be more efficient, but you doing all right.
x = A\Y'

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