I'm trying to display a 2D table

9 次查看(过去 30 天)
Hi,
i'm trying to display a 2d table for a school projet, and i'm having trouble making it work, the code seem fine to me but I can't see to find how do I call the specific case I want to display.
my code is :
for ii=1:taille
if(ii==1)
fprintf('\t%g\t\t\t\t',tableau(ii));
elseif(ii==2)
fprintf('%g\t\t\t\t',tableau(ii));
elseif(ii==3)
fprintf('%g\t\t\t\t',tableau(ii));
elseif(ii==4)
fprintf('%g\t\t\t\t\t\t\n',tableau(ii));
end
end
fprintf('\n');
fprintf('\n');
%affichage de la deuxième ligne du tableau 2D
for jj=1:taille
if(jj==1)
fprintf('\t%g\t\t\t\t',tableau(jj));
elseif(jj==2)
fprintf('%g\t\t\t\t',tableau(jj));
elseif(jj==3)
fprintf('%g\t\t\t\t',tableau(jj));
elseif(jj==4)
fprintf('%g\t\t\t\t\t\t\n',tableau(jj));
end
end
and the table displays this when i call : afficher_ecran_de_jeu([1,2,3,4;5,6,7,8])
Carte 1 Carte 2 Carte 3 Carte 4
--------- --------- --------- ---------
1 5 2 6
1 5 2 6
when it supposed to display
1 2 3 4
5 6 7 8
thank you in advance. (PS: I started learning MATlab only 4 weeks ago).

采纳的回答

Benjamin Thompson
Benjamin Thompson 2022-10-4
To read the rows and columns of a two dimensional table you need to use two indices:
In your example:
tableau(1,1) == 1
tableau(1,2) == 2
tableau(1,3) == 3
tableau(1,4) == 4
tableau(2,1) == 5
tableau(2,2) == 6
tableau(2,3) == 7
tableau(2,4) == 8
When you only use one index, MATLAB defaults to the row first data order in order to convert to a one dimensional vector, so you get 1, 5, 2, 6, 3, 7, 4, 8.

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