Plotting x(2t+2) if x(t) is defined as an anonymous function
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I have to plot the function
g = @(t) exp(-t/2)*cos(2*t*pi/3)*u(t);
for g(2t+2). I tried a couple things but I either get a blank graph or just a straight line. The only way it works is if I actually switch all the ts into (2t+2) which is excessivly time consuming
回答（1 个）
[edit: correct typos (no typos in the code) ]
You need to define u.
If you define the muliplications inside g() with ".*" instead of "*", then you can pass a vector of times to g and get an answer
Given
t=0:.2:10;
u = @(t) double(t>=0);
g = @(t) exp(-t/2).*cos(2*t*pi/3).*u(t);
plot(t,g(t))
As for 2*t+2:
hold on; %preserve existing plot
plot(t,g(2*t+2),'-r');
Works.
2 个评论
Yakov
2022-10-5
William Rose
2022-10-6
@Yakov, you're welcome. Please accept the answer if you deem it sufficient.
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2022-10-6
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