How to input new value as old value using while loop to compute relative error?
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I need help on how can I input new value as an old value
Whenever I run the code, the r_e (relative error) equation goes up and gives me a wrong answer
How do I fix this?
f_x= sin (5x) + cos (2x)
for i=1:n
f_l = f_x(x_l);
f_u = f_x(x_u);
p = (x_l+x_u)/2;
f_m = f_x(p);
if (f_l*f_m)<0
x_u=p;
elseif (f_u*f_m)<0
x_l=p;
end
p_old = p;
r_e = abs(p-p_old/(p));
table(i, :)={i-1 p r_e};
fprintf('%d %d %d \n', table{i, :});
end
0 个评论
采纳的回答
VBBV
2022-10-8
r_e = abs((p-p_old)/(p));
3 个评论
VBBV
2022-10-8
编辑:VBBV
2022-10-8
f_x= @(x) sin (5*x) + cos (2*x)
p_old = 0; % give an initial value to it
x_l =2; x_u = 10;
n = 20;
for i=1:n
f_l = f_x(x_l);
f_u = f_x(x_u);
p = (x_l+x_u)/2;
f_m = f_x(p);
if (f_l*f_m)<0
x_u=p;
elseif (f_u*f_m)<0
x_l=p;
end
r_e = abs((p-p_old)/(p));
p_old = p; % assign the p_old after relative error
table(i, :)={i-1 p r_e};
fprintf('%d %d %d \n', table{i, :});
end
give an initial value to p_old and assign the value to it after relative error inside the for loop
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