find out negative values and specific values, take it out, record those negative and specific values into a text file

4 次查看(过去 30 天)
given a (52560 x 8 double)
I need to find out the negative values from the last 3 columns, and if the value is 70% more than the sum of last 3 values and next 3 values
then replace the value with the sum of last 3 values and next 3 values divided by 6.
then record those values into a log file(txt file) (X x 3 matrix)
  3 个评论
zhi cheng
zhi cheng 2022-10-11
I just started doing it, I just done combine data from 3 txt file into 1 matrix, and split the variables.
so far this part, I have no idea how to do it

请先登录,再进行评论。

回答(1 个)

Ghazwan
Ghazwan 2022-10-11
The following code should do it. Note that because of the rules you have, you have to skip the first and the last three row.
A=[52560 x 8];
X=zeros(1,3);
for ii=4:length(A(:,1))-3
NValues=zeros(1,3);
for jj=1:3
Sum1=sum(A(ii-3:ii-1,5+jj))+sum(A(ii+1:ii+3,5+jj));
Value= (A(ii, 5+jj)-Sum1)/A(ii, 5+jj);
if A(ii, 5+jj)<0 && Value>0.7
NValues(1,jj)=A(ii,5+jj);
A(ii,5+jj)=Sum1/6;
end
end
if sum(abs(NValues))~=0, X=[X;NValues]; end
end
if length(X(:,1))>1, X=X(2:end,:); end
xlswrite('Values.xlsx',X,1);

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

产品


版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by