extracting the second column of all cells of a struct

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Sahar khalili
Sahar khalili 2022-10-11
评论： Sahar khalili 2022-10-12
I have a struct, x1_surf, that contains 1070 cells, each cell has 4 cells, now I want to extract the second column of the inner cells with the order.
This is x1_surf
This is the x1_surf{1,1}
now, I want to extract the second column of all inccer cells with the correct order, I mean x1_surf{1,:}{1,2}
I write a script like that:
It works correcly for some files, however for some other files, the order of the date is mixed up and they are not in the right order. Could anyone help me how I can rewise it?

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采纳的回答

David Hill
David Hill 2022-10-11
for k=1:length(x1_surf)
x2_surf{k}=x1_surf{k}{2};
end
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David Hill
David Hill 2022-10-12
Ran in:
I am assuming you just want just one listing of all the date-times.
load('x1_surf.mat');
x2_surf=[];
for k=1:length(x1_surf)
x2_surf=[x2_surf;x1_surf{k}{2}];
end
x2_surf(1:20)
ans = 20×1 datetime array
11-Sep-2019 13:29:00 11-Sep-2019 13:39:00 11-Sep-2019 13:49:00 11-Sep-2019 13:59:00 11-Sep-2019 14:09:00 11-Sep-2019 14:19:00 11-Sep-2019 14:29:00 11-Sep-2019 14:39:00 11-Sep-2019 14:49:00 11-Sep-2019 14:59:00 11-Sep-2019 15:09:00 11-Sep-2019 15:19:00 11-Sep-2019 15:29:00 11-Sep-2019 15:39:00 11-Sep-2019 15:49:00 11-Sep-2019 15:59:00 11-Sep-2019 16:09:00 11-Sep-2019 16:19:00 11-Sep-2019 16:29:00 11-Sep-2019 16:39:00

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