I gave the initial condition correctly still the program not working.
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ti = 0;
tf = 70E-8;
tspan=[ti tf];
k = (0.62).*10^(-5);
% y0= [(10e-6)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
% (10e-6)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
% (10e-6)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
% (10e-6)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
% (10e-6)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
% ((-3.14).*rand(5,1) + (3.14).*rand(5,1))];
y0 = [ 0.00001; 0.00001; 0.00001; 0.00001; 0.00001;
0.00001; 0.00001; 0.00001; 0.00001; 0.00001; 2.5669; 2.0482; 2.0454; -0.7968; 0.2303];
yita_mn = [
0 1 0 0 1;
1 0 1 0 0;
0 1 0 1 0;
0 0 1 0 1;
1 0 0 1 0;
]*(k);
N = 5;
tp = 1E-12;
[T,Y]= ode45(@(t,y) rate_eq(t,y,yita_mn,N),tspan./tp,y0);
figure(1)
plot(T./t,(Y(:,16)),'linewidth',0.8);
hold on
for m = 16:20
plot(T./t,(Y(:,m)),'linewidth',0.8);
end
hold off
grid on
xlabel("time")
ylabel("phase difference")
set(gca,'fontname','times New Roman','fontsize',18,'linewidth',1.8);
function dy = rate_eq(t,y,yita_mn,N,o)
dy = zeros(4*N,1);
dGdt = zeros(N,1);
dAdt = zeros(N,1);
dOdt = zeros(N,1);
P = 0.5;
a = 1;
T = 2E3;
Gt = y(1:3:3*N-2);
At = y(2:3:3*N-1);
Ot = y(3:3:3*N-0);
k = (0.62).*10^(-5);
for i = 1:N
dGdt(i) = (P - Gt(i) - (1 + 2.*Gt(i)).*(At(i))^2)./T ;
dAdt(i) = (Gt(i).*(At(i)));
dOdt(i) = -a.*(Gt(i));
for j = 1:N
dAdt(i) = dAdt(i)+yita_mn(i,j).*(At(j))*sin(Ot(j)-Ot(i));
dOdt(i) = dOdt(i)+yita_mn(i,j).*((At(j)/At(i)))*cos(Ot(j)-Ot(i));
end
end
dy(1:3:3*N-2) = dGdt;
dy(2:3:3*N-1) = dAdt;
dy(3:3:3*N-0) = dOdt;
n1 = (1:5)';
n2 = circshift(n1,-1);
n16 = n1 + 15;
n17 = circshift(n16,-1);
n20 = circshift(n16,1);
j2 = 3*(1:5)-1;
j5 = circshift(j2,-1);
j8 = circshift(j2,-2);
j19 = circshift(j2,1);
dy(n16) = -a.*(Gt(n2)-Gt(n1)) + (k).*(y(j2)./y(j5)).*cos(y(n16)) - (k).*(y( j5)./y(j2)).*cos(y(n16)) + (k).*(y(j8)./y(j5)).*cos(y(n17)) - (k).*(y(j19)./y(j2)).*cos(y(n20));
end
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采纳的回答
Walter Roberson
2022-10-11
y0 = [ 0.00001; 0.00001; 0.00001; 0.00001; 0.00001;
0.00001; 0.00001; 0.00001; 0.00001; 0.00001; 2.5669; 2.0482; 2.0454; -0.7968; 0.2303];
That is 15 initial values.
for m = 16:20
plot(T./t,(Y(:,m)),'linewidth',0.8);
end
But you are trying to plot assuming 20 results. The only way to get 20 results is to have 20 or more initial values.
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更多回答(1 个)
Benjamin Thompson
2022-10-11
circshift returns a vector of the same length as its input. So, j2, j5, j8, and j19 are vectors and not scalar values as the line having the failure seems to expect. You can use breakpoints in your script in MATLAB to investigate further and debug the problems.
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